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Jet001 [13]
3 years ago
14

13 is 25% of what number

Mathematics
2 answers:
Sladkaya [172]3 years ago
6 0
Hack way
25%=1/4
13 is 1/4 of something
1/4 times 4=4/4=1

therefor
13 times 4=1 whole
13*4=52
the original number is 52
marshall27 [118]3 years ago
3 0
13 is 25% of the number 52.
13/25%(or .25) = 52 >>> 13/0.25 = 52
I divided because if you multiply, you get 3.25, which isn't what your looking for. :D
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A recent college graduate is planning to take the first three actuarial examinations in the coming summer. She will take the fir
erica [24]

Answer:

(a) 0.7

(b) \frac 13

Step-by-step explanation:

Let E_1, E_2, and E_3 be the events of passing the 1st, 2nd, and 3rd exam individually.

Given that P(E_1)=0.9\;\cdots(i)

where P(E_1) denotes the probability of passing the 1st exam.

Condition for passing the second exam is, at first, the candidate must have to pass the 1st exam.

So, P\left(\frac{E_2}{E_1}\right)=0.8\;\cdots(ii)

where P(E_2/E_1) denotes the probability of passing the 2nd exam when she already passed the 1st exam (given, 0.8).

Similarly, as the conditional probability of passing the 3rd exam is 0.7, and the condition for this is, at first, she must have to pass the 1st and 2nd exam. i.e,

P\left(\frac{E_2}{P(E_2/E_1)}\right)=0.7\;\cdots(iii)

(a) For passing all the exams, the condition is, at first, she has to pass the 1st and 2nd exam, then she has to pass the 3rd exam too. The probability for this conditional has been given as 0.7.

So, the probability that she passes all three exams is 0.7.

(b) Given that she didn't pass all three exams that means she either failed in 1st exam or she passed the 1st and failed in 2nd exam or she passed both 1st and 2nd but failed in the 3rd exam.

Let F be the event that she didn't pass all three exams. So,

P(F)=(1-P(E_1))+\left(1-\frac{P(E_2)}{P(E_1)}\right)+\left(1-\frac{P(E_2)}{P(E_2/E_1)}}\right)

\Rightarrow P(F)=(1-0.9)+(1-0.8)+(1-0.7)=0.6

Lef F_2 be the event that she failed the 2nd exam, so

P(F_2)=1-\frac{P(E_2)}{P(E_1)}

\Rightarrow P(F_2)=1-0.8=0.2

So, the conditional probability that she failed the 2nd exam is

P\left(\frac{F_2}{F}\right)=\frac{P(F_2)}{P(F)}

\Rightarrow P\left(\frc{F_2}{F}\right)=\frac{0.2}{0.6}=\frac{1}{3}=0.33

5 0
3 years ago
32 is what percent of 160?
jonny [76]


32/160 = 0.20

so 32 is 20% of 160

7 0
3 years ago
If f(x)=4x+3 and g(x)=x^2-3 then f(g(2))
grandymaker [24]

Answer:

<em>f(g(2))=7</em>

Step-by-step explanation:

<u>The Composite Function</u>

Given f(x) and g(x) as real functions, the composite function (f\circ g)(x) is defined as:

(f\circ g)(x)=f(g(x))

It can be found by substituting g into f.

The given functions are:

f(x)=4x+3

g(x)=x^2-3

It's required to find f( g( 2 ) )

Find g(2):

g(2)=2^2-3

Operating:

g(2)=4-3 =1

g(2)=1

Now find f(1):

f(1)=4(1)+3

f(1)=4+3 =7

Thus:

f( g( 2 ) )=7

4 0
3 years ago
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vagabundo [1.1K]
2 is a common multiple for 8,12,10

3 0
2 years ago
Read 2 more answers
What is nonconsecutive quadrilateral?
WITCHER [35]

Answer:

NON CONSECUTIVE SIDES.

Step-by-step explanation:

The sides which are not adjacent to each other. In case of quadrilaterals the non consecutive side is the opposite side.

6 0
3 years ago
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