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LenaWriter [7]
3 years ago
5

Simplify 8 + 3{x - 2[x + 5(x + 3)]}. -33x + 82 33x - 82 -33x - 82

Mathematics
1 answer:
77julia77 [94]3 years ago
5 0

Answer:

<h2>-33x - 82</h2>

Step-by-step explanation:

Use

PEMDAS:

P      Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

and the distributive property a(b + c) = ab + ac.

1)\qquad5(x+3)=5x+15\\\\2)\qquad x+5(x+3)=x+5x+15=6x+15\\\\3)\qquad2[x+5(x+3)]=2(6x+15)=12x+30\\\\4)\qquad x-2[x+5(x+3)]=x-(12x+30)=x-12x-30=-11x-30\\\\5)\qquad3\{x-2[x+5(x+3)]\}=3(-11x-30)=-33x-90\\\\6)\qquad8+3\{x-2[x+5(x+3)]\}=8+(-33x-90)=-33x-82

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y-y1=m(x-x1)
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7 0
3 years ago
Who can help me please
lakkis [162]
The dimensions of the bottom of the drawer are:
20 cm × 40 cm

So the area is : 800 cm² (rectangular shaped)

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\pir²
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7 0
3 years ago
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7 0
3 years ago
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4 0
1 year ago
i need help with this equation please there are two more possible answers that were cut off they are 17,2% and 19,5%
Margarita [4]

Consider that the experimental probability of an event is based upon the previous trials and observations of the experiment.

The experimental probability of occurrence of an event is given by,

\text{Probability of an event}=\frac{\text{ Number of outcomes that favoured the event}}{\text{ Total number of trials or outcomes}}

As per the problem, there are a total of 1230 trials of rolling a dice.

And the favourable event is getting a 2.

The corresponding experimental probability is calculated as,

\begin{gathered} P(\text{ getting a 2})=\frac{\text{ No. of times 2 occurred}}{\text{ Total no. of times the dice is thrown}} \\ P(\text{ getting a 2})=\frac{172}{1230} \\ P(\text{ getting a 2})\approx0.13984 \\ P(\text{ getting a 2})\approx13.98\text{ percent} \end{gathered}

Thus, the required probability is 13.98% approximately.

Theref

7 0
1 year ago
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