Answer:
After finding the prime factorization of $2010=2\cdot3\cdot5\cdot67$, divide $5300$ by $67$ and add $5300$ divided by $67^2$ in order to find the total number of multiples of $67$ between $2$ and $5300$. $\lfloor\frac{5300}{67}\rfloor+\lfloor\frac{5300}{67^2}\rfloor=80$ Since $71$,$73$, and $79$ are prime numbers greater than $67$ and less than or equal to $80$, subtract $3$ from $80$ to get the answer $80-3=\boxed{77}\Rightarrow\boxed{D}$.
Step-by-step explanation:
hope this helps
Answer:
-11.3
Step-by-step explanation:
You start off at -11 and count down and it ends up at -11.3
Answer:
It does
Step-by-step explanation:
Basically:
-1×x=-1x
When doing Algebra, You never write 1x, you just write x, so therefore it should not be -1x but -x
I hope this helped you, and please give be brainliest.