Only 3 and 9 are both the subset of odd numbers and the subset of multiples of 3.
Answer:
Given
x+y+z=0
⟹x+y=−z
Cubing on both sides
(x+y) 3 =(−z) 3
⟹x 3 +y 3 +3x 2y+3xy 2 =−z 3
⟹x 3 +y 3 +3xy(x+y)=−z 3
⟹x 3+y 3+3xy(−z)=−z 3
⟹x 3 +y 3−3xyz=−z 3
⟹x 3 +y 3 +z 3 =3xyz
Step-by-step explanation:
Hope it is helpful.....
Answer:
It is a solution of the ordered pair.
Step-by-step explanation:
The y intercept is (0,-2)
Answer:
I have no clue as to what the options were, but the answer is 61 and three-fifths.
Step-by-step explanation:
<em>Well, the fraction options were a little distorted, so I'll work it out anyway.</em>
<em />
7 • 8 4/5
7(8 + 4/5)
<em>7 • 8 is 56, and 7 • 4/5 is 28/5.</em>
56 + 28/5
<em>28/5 as a mixed-number fraction (I think that's what it's called) is 5 3/5.</em>
56 + 5 + 3/5
61 + 3/5
61 3/5 (61 and three-fifths)
There!
<em>(Sorry about not getting the options...)</em>
