1. 0.33 M
2. 0.278 M
<h3>Further explanation</h3>
Molarity is a way to express the concentration of the solution
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
1. 0.350 mol of NaOH in 1.05 L of solution.
n=0.35
V=1.05 L
Molarity :
2. 14.3 g of NaCl in 879 mL of solution.
mol NaCl(MW=58.5 g/mol) :
Molarity :
Answer:
Molar mass = 30.026 g/mol
Explanation:
Let Molar mass be mm
mm of CH2O = 12.01 + 2(1.008) + 16.00
= 12.01 + 2.016 + 16.00 = 30.026 g/mol
Answer:
E) A, B, and C
Explanation:
Syn addition refers to the addition of two substituents on the same face or side of a double bond. This differed from anti addition which a occurs across opposite face of the double bond.
Hydrogenation, hydroboration and dihydroxylation all involve syn addition to the double bond, hence the answer chosen above.
Answer:
b. 51.63%
Explanation:
Step 1: Given data
- Mass of the sample: 1.253 g
- Moles of oxalate (C₂O₄²⁻): 7.35 × 10⁻³ mol
Step 2: Calculate the mass corresponding to 7.35 × 10⁻³ moles of oxalate
The molar mass of C₂O₄²⁻ is 88.02 g/mol.
7.35 × 10⁻³ mol × 88.02 g/mol = 0.647 g
Step 3: Calculate the mass percent of oxalate in the sample
% w/w = mass of oxalate / mass of the sample × 100%
% w/w = 0.647 g / 1.253 g × 100%
% w/w = 51.63%