Answer:
A. Acidic
B. Neutral
C. Basic
D. Acidic
E. Basic
Explanation:
The reaction of salts with water to give aqueous solutions which are either acidic, basic or neutral is known as salt hydrolysis. Salts that are produced from the reaction of strong acids and weak bases give acidic solutions. Salts that are produced the reaction between weak acids and strong bases give basic solutions. Neutral solutions are obtained from salts produced bynthe reaction of strong acids and strong bases.
The hydrolysis of the given salts are shown below:
A. AlCl₃ + 3 H₂O ---> 3 HCl + Al(OH)₃
The aqueous solution produced will be acidic since HCl is a strong acid while Al(OH)₃ is a weak base.
B. NaBr + H₂O ----> HBr + NaOH
The aqueous solution produced will be neutral since HBr is a strong acid and NaOH is strong base as well.
C. NaClO + H₂O ----> HClO + NaOH
The aqueous solution produced will be basic since HClO is a weak acid while NaOH is a strong base.
D. CH₃NH₃NO₃ + H₂O ----> HNO₃ + CH₃NH₂ + H₂O
The aqueous solution produced will be acidic since HNO₃ is a strong acid while CH₃NH₂ is a weak base.
E. Na₂SO₃ + 2 H₂O ----> H₂SO₃ + 2 NaOH
The aqueous solution produced will be basic since H₂SO₃ is a weak acid while NaOH is a strong base.
motion
Explanation:
it works in our daily life
Answer:
177.1 L
Explanation:
The excersise can be solved, by the Ideal Gases Law.
P . V = n . R . T
In first step we need to determine the moles of gas:
We convert T° from, C° to K → 20°C + 273 = 293K
We convert P from mmHg to atm → 760 mmHg = 1atm
1Dm³ = 1L → 190L
We replace: 190 L . 1 atm = n . 0.082 . 293K
(190L.atm) / 0.082 . 293K = 7.91 moles.
We replace equation at STP conditions (1 atm and 273K)
V = (n . R .T) / P
V = (7.91 mol . 0.082 . 273K) / 1atm = 177.1 L
We can also make a rule of three:
At STP conditions 1 mol of gas occupies 22.4L
Then, 7.91 moles will be contained at (7.91 . 22.4) /1 = 177.1L
Answer:
0.053moles
Explanation:
Hello,
To calculate the number of moles of gas remaining in his after he exhale, we'll have to use Avogadro's law which states that the volume of a given mass of gas is directly proportional to its number of moles provided that temperature and pressure are kept constant. Mathematically,
V = kN, k = V / N
V1 / N1 = V2 / N2= V3 / N3 = Vx / Nx
V1 = 1.7L
N1 = 0.070mol
V2 = 1.3L
N2 = ?
From the above equation,
V1 / N1 = V2 / N2
Make N2 the subject of formula
N2 = (N1 × V2) / V1
N2 = (0.07 × 1.3) / 1.7
N2 = 0.053mol
The number of moles of gas in his lungs when he exhale is 0.053 moles
B. is ur answer I bieleve