Answer:
Any negative integer and any positive integer.
Like -5 and 3.
Step-by-step explanation:
In multiplication, <u>a positive number and a negative number will result in a negative product</u>.
So, you can use any positive integer and multiply it by any negative integer to get a negative product.
Using the integers I gave:
<em>Brainilest Appreciated. </em>
Answer:
5/6
Step-by-step explanation:
Only 5 is not divisible by 12
Amount of grass in the backyard is 0.641 square yards
<h3>
What is a square?</h3>
Any 2-dimensional figure bounded by 4 sides whose all sides are equal and all the angles are 90° is called a square.
<h3>How to find the area of a square?</h3>
Area of a square can be found by squaring the length of one of its sides.
<h3>What is a rectangle?</h3>
Any 2-dimensional figure bounded by 4 sides whose opposites sides are equal and parallel and all the angles are 90° is called a rectangle.
<h3>How to find out area of a rectangle?</h3>
Area of a rectangle can be found by multiplying its length by its breadth.
<h3>How to calculate the area in the given problem?</h3>
The given figure is a combination of multiple figures.
- 1 square of length 3 cm on top
- 1 rectangle in the middle whose length is ( 2 + 3) cm = 5 cm, and breadth is 3 cm
- 1 larger rectangle at the bottom whose length is 10 cm and breadth is 3 cm.
- We will have to calculate these areas and sum up the areas to get the entire area.
- Area of the square at the top = ( 3 x 3) cm² = 9 cm²
- Area of the middle rectangle = ( 5 x 3) cm² = 15 cm²
- Area of the bottom rectangle = (10 x 3) cm² = 30 cm²
∴ Total area of the backyard = ( 9 + 15 + 30) cm² = 54 cm²
Amount of grass in the backyard = (54 x 0.109² ) square yards
= 0.641 square yards ( 1 cm = 0.109 yards)
Find out more information about area calculations here: brainly.com/question/1297098
#SPJ2
Answer:
$6.96
Step-by-step explanation:
5.25% of $5.79
5.79 × 5.25/100 = $0.303975 or $0.30
15% of $5.79
5.79 × 15/100 = $0.8685 or $0.87
total
$0.29 + $0.87 + $5.79 = $6.96
I do not know bro. Have you tried
