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3 years ago

Confusion help please

Mathematics

2 answers:

SashulF [63]3 years ago

4 0

Answer:

Step-by-step explanation:

what do u need help with

Fofino [41]3 years ago

3 0

Answer:

Step-by-step explanation:

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Marta wants to purchase charms for her necklace. Each charm cost $1.59. She wants to spend no more than $20 for the charms. Whic

Svetllana [295]

Which inequality represents this situation ?

1.59×n < 20

How many charms can Marta purchase ?

20 : 1.59 = 12 (+$0.92)

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3 years ago

What is the equation of the line?

VikaD [51]

The equation is "x=0", because the x intercepts at the x axis with no y-intercept.

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3 years ago

ASAP<br> - WILL MARK BRIANIST<br> Please explain

marissa [1.9K]

Answer:

D 26 batches

Step-by-step explanation:

for each cup of cranberries, 4 batches of scones can be made

6 1/2 * 4 = 24 + 2 = 26

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3 years ago

Read 2 more answers

Reporting cheating What proportion of students are willing to report cheating by other students? A student project put this ques

KonstantinChe [14]

Answer:

0.1105

Step-by-step explanation:

We know that question about reporting a cheating is asked to 172 students.

So the sample size would be n=172.

Out of 172 undergraduate students only 19 students answered "yes". It means that only 19 out of 172 students are willing to report cheating and so x=19.

According to definition of proportion

proportion=number of favorable outcome/total number of outcome

p=x/n

we are given that x=19 and n=172 so,

p=19/172=0.1105.

Hence according to given data 11.05% of students are wiling to report cheating by other students.

7 0

3 years ago

Suppose you do not know the population mean fee charged to H&R Block customers last year. Instead, suppose you take a sample

puteri [66]

Answer:

i $\to$ a

$n = 96040000$

i $\to$ b

$n_1 =24010000$

i $\to$ c

$n_2 =41602500$

ii $\to$ a

$E = 58.16$

ii $\to$ b

$291.84 < \mu < 408.16$ \

ii $\to$ c

There is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval

Step-by-step explanation:

From the question we are told that

The sample size is $n = 8$

The sample mean is $\= x = \$ 350$

The sample standard deviation is $\$ 100$

Considering question i

i $\to$ a

At $E = 0.02$

given that the confidence level is 95% = 0.95

the level of significance would be $\alpha =1-0.95 = 0.05$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha }{2} } = 1.96$

So the sample size is mathematically evaluated as

$n = [ \frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ]^2$

=> $n =[ \frac{ 1.96 * 100}{ 0.02} ]^2$

=> $n = 96040000$

i $\to$ b

At $E_1 = 0.04$ and confidence level = 95% => $\alpha_1 = 0.05$ => $Z_{\frac{\alpha_1 }{2} } = 1.96$

$n_1 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_1} ]^2$

=> $n_1 =[ \frac{ 1.96 * 100}{ 0.04} ]^2$

=> $n_1 =24010000$

i $\to$ c

At $E_2 = 0.04$ confidence level = 99% => $\alpha_2 = 0.01$

The critical value of $\frac{\alpha_2 }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha_2 }{2} } = 2.58$

=> $n_2 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_2} ]^2$

=> $n_2 =[ \frac{ 2.58 * 100}{ 0.04} ]^2$

=> $n_2 =41602500$

Considering ii

Given that the level of significance is $\alpha = 0.10$

Then the critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

substituting values

$E = 1.645 * \frac{100 }{\sqrt{8} }$

$E = 58.16$

Generally the 90% confidence interval is mathematically evaluated as

$\= x - E < \mu < \= x + E$

=> $350 - 58.16 < \mu < 350 + 58.16$

=> $291.84 < \mu < 408.16$

So the interpretation is that there is 90% confidence that the mean fee charged to H&R Block customers last year is in the interval .So there is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval.

8 0

3 years ago