Answer:
213`334
Step-by-step explanation:
sry lol i want points i apologize
Make sure you don't spend to much and have no more money left
Answer:
The groups walking speed is
or ![1.875\frac{miles}{hour}](https://tex.z-dn.net/?f=1.875%5Cfrac%7Bmiles%7D%7Bhour%7D)
Step-by-step explanation:
we know that
To find the speed divide the distance by the time
so
![\frac{(3/8)}{(1/5)}=\frac{15}{8}\frac{miles}{hour}](https://tex.z-dn.net/?f=%5Cfrac%7B%283%2F8%29%7D%7B%281%2F5%29%7D%3D%5Cfrac%7B15%7D%7B8%7D%5Cfrac%7Bmiles%7D%7Bhour%7D)
Convert to mixed number
![\frac{15}{8}=\frac{8}{8}+\frac{7}{8}=1\frac{7}{8}\frac{miles}{hour}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B8%7D%3D%5Cfrac%7B8%7D%7B8%7D%2B%5Cfrac%7B7%7D%7B8%7D%3D1%5Cfrac%7B7%7D%7B8%7D%5Cfrac%7Bmiles%7D%7Bhour%7D)
Answer
f(t)=2cos(t)
Step-by-step explanation:
let's describe the situation first, a fly is starting 2 meters from the bulb and flies towards the bulb and when it is really close to the bulb, it flies 2 meters further away from the bulb this means that it reaches d = 0m (distance from the bulb) and then flies further 2 meters so d = -2m.
it this point the fly returns back and touches the bulb and flies away (ends it's oscillatory motion ). d = 0 again and story ends here.
here if we want to model this problem with time function , the cosine function seems the best fit with amplitude of 2, so the answer is f(t) = 2cos(t).
Now you can ask why cosine function? well if you look at the graph or the plot of the function it perfectly captures the physical situation going on here in this problem.
Domain is 0 to 2
because it is one complete cycle and the range is -2 to +2.