Answer:
x = 1.27
y = 5.18
Step-by-step explanation:
to solve this system of equation by simultaneous equation we say that let
3x+y=9.............................. equation 1
-5x+2y=4 .......................... equation 2
from equation 1
3x+y=9.............................. equation 1
y = 9 -3x.............................. equation 3
substitute the value of y = 9 -3x into equation 2
-5x+2y=4 .......................... equation 2
-5x + 2( 9 -3x) = 4
-5x + 18 - 6x = 4
collect the like terms
18 - 4 = 6x + 5x
14 = 11x
divide both side by 11
14/11 = 11x/11
x = 14/11
x = 1.27
put the value of x = 1.27 into equation 3
y = 9 -3x.............................. equation 3
y = 9 - 3( 1.27)
y = 9 - 3.82
y = 5.18
<em>to check if you are correct put the value of x and y into either equation 1 or equation 2.</em>
<em>3x+y=9.............................. equation 1</em>
<em>3( 1.27) + 5.18 = 9</em>
<em>3.81 + 5.18 = 9</em>
<em>9 = 9</em>
Answer:
2800
Step-by-step explanation:
Just round the 43 to 40 and the 68 to 70. So the problem then converts to 40x70 to get a rough estimate. 40x70=2800
Answer:
25 ft^2
Step-by-step explanation:
In direct variation, if y varies directly with x, then the equation has the form
y = kx,
where k is the constant of proportionality. y is proportional to x.
Let's call the area y and the distance x.
Here, the area varies with the square of the distance, so the equation has the form
y = kx^2
Here, y is proportional to the square of x.
We can find the value of k by using the given information.
y = kx^2
When x = 20 ft, y = 16 ft^2.
16 = k(20^2)
k = 16/400
k = 1/25
The equation of the relation is:
y = (1/25)x^2
Now we use the equation we found to answer the question.
What is y (the area) when x (the distance) is 25 ft?
y = (1/25)x^2
y = (1/25)(25^2)
y = 25
Answer: 25 ft^2
Going by the data given, the best center of distribution to use in terms of mean and median is D) Mean for Bakery A because the data is symmetric; median for Bakery B because the data is not symmetric.
<h3>What centers of distribution should be used?</h3>
The mean should be used for data sets that are symmetric while the median should be used for data that is not symmetric.
The data is said to be symmetric when the mean and median are equal or very close.
Bakery A mean:
= (45 + 52 + 51 48 + 61 + 34 + 55 46) / 8
= 49
Bakery A median is 49.5
Bakery B mean:
= (48 42 + 25 45 + 57 + 10 + 43 + 46 ) / 8
= 39.5
Bakery B median is 44.
This shows that Bakery A data is symmetric so the best center of distribution to use is mean.
Bakery B is not symmetric so the center of distribution to use is median.
Find out more on symmetric data at brainly.com/question/7130507
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