All categories

3 years ago

WILL GIVE BRAINLIEST

Mathematics

1 answer:

marshall27 [118]3 years ago

6 0

Answer:

Look below.

Step-by-step explanation:

You need to use the Pythagorean theorem.

Formula: a^2+b^2=c^2

a=10 b=6 c=?

10^2+6^2=c^2

c≈11.6619

Their isnt any choice that has this number but if you put option D into the calculator you will get 11.66 which is correct. Option D is correct for side A.

You might be interested in

Aha please help!!!!! im a bit confused lol

Stels [109]

Answer:

e : g = 2 : 7

Step-by-step explanation:

e/f = 3/7

e = 3f/7

f/g = 2/3

g = 3f/2

e/g = (3f/7)/(3f/2) = 2/7

3 0

2 years ago

Find the percent cost of the total spent on each equipment $36, fees $158, transportation $59

maksim [4K]

Answer: Therefore, Option 'A' is correct.

Step-By-Step explanation:

Since we have given that

Amount spent on equipment = $36

Amount spent on fees = $158

Amount spent on transportation = $59

Total amount spent by them is given by

$36+158+59=\$253$

Percent cost of equipment of the total amount is given by

$\frac{36}{253}\times 100=14.2\%$

Percent cost of fees of the total amount is given by

$\frac{158}{253}\times 100\\\\=62.45\%$

Percent cost of transportation of the total amount is given by

$\frac{59}{100}\times 100\\\\=23.3\%$

Hence, Percent cost of the total spent on each is

14%, 62%, 23%.

Therefore, Option 'A' is correct.

6 0

3 years ago

How many different ways can you arrange 100 numbers?

Semenov [28]

10,000 or 100,000 so I hope it helps

4 0

3 years ago

Use an appropriate Taylor series to find the first four nonzero terms of an infinite series that is equal to sin(5/2).

koban [17]

Answer:

2.5, -2.61, 0.81, -0.12

Step-by-step explanation:

The taylor series of the function sin(x) around zero is given by

$sin(x)=\sum_{n=0}^{\infty}\dfrac{(-1)^k}{(2k-1)!}x^{2k+1}=x-\dfrac{x^3}{3!}+\dfrac{x^5}{5!}-\dfrac{x^7}{7!}$

Therefore,

$\sin(\frac{5}{2})=\dfrac{5}{2}-\dfrac{[\frac{5}{2}]^3}{3!}+\dfrac{[\frac{5}{2}]^5}{5!}-\dfrac{[\frac{5}{2}]^7}{7!}+...$

hence the first four nonzero terms of the series are

$\dfrac{5}{2}=2.5\\\\-\dfrac{[\frac{5}{2}]^3}{3!} \approx -2.61\\\\\dfrac{[\frac{5}{2}]^5}{5!} \approx 0.81\\\\-\dfrac{[\frac{5}{2}]^7}{7!} \approx -0.12$