Use the points shown on the graph to the right

Now solve in simplest terms: 4/5+4/5<br> please help no links or files

xxTIMURxx [149]

Answer:

1 and 3/5

Step-by-step explanation:

4/5+4/5=8/5

8÷5

=1 3/5

8 0

2 years ago

PLEASE HELP!!!!!<br><br> find the area of the polygon.

CaHeK987 [17]

Answer:

2 cm is were youll find the polygon at. it shouldnt be hard to see the area of were the polygon is

7 0

2 years ago

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Country A has a growth rate of 4.9% per year. The population is currently 4 comma 151,000, and the land area of Country A is 1

kvv77 [185]

Answer:

There will be one person on 1 square yard of land after 1,892,147.588 years.

Step-by-step explanation:

Continuous exponential growth formula:

$P(t)=Pe^{rt}$

P(t)= Population after t years.

P= Initial population

r=rate of growth.

t= time in year

Given that,

Growth rate of country A (r)= 4.9% per year=0.049 per year.

Initial population (P)= 151,000.

Land area of country area= 14,000,000,000 square yards.

There will be one person on one square yard of land.

So, there will be 14,000,000,000 person for 14,000,000,000 square yard of land in country A.

P(t)=14,000,000,000 person

$\therefore 14,000,000,000= 151,000 e^{0.049t}$

$\Rightarrow e^{0.049t}=\frac{ 14,000,000,000}{ 151,000}$

Taking ln both sides

$\Rightarrow ln|e^{0.049t}|=ln|\frac{ 14,000,000,000}{ 151,000}|$

$\Rightarrow {0.049t}=ln|\frac{ 14,000,000,000}{ 151,000}|$

$\Rightarrow t}=\frac{ln|\frac{ 14,000,000,000}{ 151,000}|}{0.049}$

$\Rightarrow t}=1,892,147.588$ years

There will be one person for every square yard of land after 1,892,147.588 years.

7 0

3 years ago

In ΔJKL, k = 9.6 cm, l = 2.7 cm and ∠J=43°. Find ∠L, to the nearest 10th of a degree.

Bogdan [553]

Answer:

L = 10.64°

Step-by-step explanation:

From the given information:

In triangle JKL;

line k = 9.6 cm

line l = 2.7 cm; &

angle J = 43°

we are to find angle L = ???

We can use the sine rule to determine angle L:

i.e

$\dfrac{j}{SIn \ J} = \dfrac{l}{ SIn \ L}$

Using Pythagoras rule to find j

i,e

j² = k² + l²

j² = 9.6²+ 2.7²

j² = 92.16 + 7.29

j² = 99.45

$j = \sqrt{99.45}$

j = 9.97

∴

$\dfrac{9.97}{Sin \ 43} = \dfrac{2.7}{ Sin \ L}$

${9.97 \times Sin (L ) = (2.7 \times Sin \ 43)$

$= Sin \ L = \dfrac{ (2.7 \times Sin \ 43)}{9.97 } \\ \\ = Sin \ L = \dfrac{ (2.7 \times 0.6819)}{9.97 } \\ \\ = Sin \ L = 0.18466 \\ \\ L = Sin^{-1} (0.18466) \\ \\ L = 10.64 ^0$

3 0

3 years ago

What is the value of x in the circle below? If necessary round your answer to the nearest tenth. I AM FAILING THIS CLASS I JUST

emmainna [20.7K]

Since we know that the 38 is being bisected (which we can tell by the fact that the line hits it perpendicularly), we know that from the intersection to the edge of the circle is 19. From this we can create a right triangle in which the legs are 10 and 19 and the hypotenuse is a radius of the circle. Since x is also a radius of the circle, all we have to do is use that information to find the hypotenuse using the Pythagorean Theorem and we have x.

Pythagorean Theorem
$a^{2}$ + $b^{2}$ = $c^{2}$
$10^{2}$ + $19^{2}$ = $x^{2}$
100 + 361 = $x^{2}$
461 = $x^{2}$
x = $\sqrt{461}$ or about 21.47

8 0

3 years ago

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