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3 years ago

Describe how to use a tens fact to find the difference for 15-8

2 answers:

8 0

Because you need to subtract from 10, you need to do 10-8. Then you will add 5 since you took away 5 to subtract from 10.

olchik [2.2K]3 years ago

7 0

Fiest do 15 with 5 is 20 so 8 - 5 = 3 so 20 and 3 is 23

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Find the suface area of the regular pyrimid 15, 12, r 7.5

Pani-rosa [81]

The area is 5 cm^2 of the pyramid

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3 years ago

HELP ASAP PLZ<br> find the perimeter of the figures shown below.

AlladinOne [14]

Answer:

Step-by-step explanation:

6.2 x 5 = 31

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2 years ago

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Find the Mid point of (-5,-9) (-7,-4)

lyudmila [28]

Answer: ( -6 , -6.5 )

Step-by-step explanation:

The formula for calculating Mid - point is given by

M = ( $\frac{x_{1}+x_{2}}{2}$ , $\frac{y_{1}+y_{2}}{2}$ )

$x_{1}$ = -5

$x_{2}$ = -7

$y_{1}$ = -9

$y_{2}$ = -4

substituting into the formula , we have

M = $\frac{-5-7}{2}$ , $\frac{-9-4}{2}$

M = $\frac{-12}{2}$ , $\frac{-13}{2}$

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8 0

3 years ago

A) 3√2 - 5√8 + 2√20

tigry1 [53]

Answer:

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Step-by-step explanation:

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2 years ago

How to right a radical in exponential form

Law Incorporation [45]

Answer:

$\sqrt[n]{x}=x^{\frac{1}{n}}$

Step-by-step explanation:

The index of a radical is the denominator of a fractional exponent, and vice versa. If you think about the rules of exponents, you know this must be so.

For example, consider the cube root:

$\sqrt[3]{x}\cdot \sqrt[3]{x}\cdot \sqrt[3]{x}=(\sqrt[3]{x})^3=x\\\\(x^{\frac{1}{3}})^3=x^{\frac{3}{3}}=x^1=x$

That is ...

$\sqrt[3]{x}=x^{\frac{1}{3}} \quad\text{radical index = fraction denominator}$

3 0

3 years ago