Describe how to use a tens fact to find the difference for 15-8

Please help<br> With the following question

Vikki [24]

The equation youre using is y=mx+b

b is the y int which 3 and the slope between the points is 5/2 so your equation is y=5/2x+3

4 0

3 years ago

When stating the null and alternative hypotheses, the hypotheses are: Select one: a. Always about the statistic only b. Always a

Nata [24]

Answer:

D. Always about the parameter only

Step-by-step explanation: A Null Hypothesis is a hypothesis used in statistics to show that there is no variation among the variables of interest. A Null Hypothesis also can be said to be giving a proposal that there is not significant difference between the observed data.

An alternative hypothesis is a hypothesis in statistics given contrary to the Null Hypothesis,a Null hypothesis can also be seen in statistics as stating that something is happening among the data.

3 0

2 years ago

Some research suggests that police officers are more likely to make an arrest in the presence of bystanders. If mentally disorde

zmey [24]

Answer:

$t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638$

$p_v =P(t_{(19)}>1.638)=0.0589$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=7.03$ represent the sample mean

$s=9.42$ represent the sample standard deviation

$n=20$ sample size

$\mu_o =3.58$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 3.58 :

Null hypothesis: $\mu \leq 3.58$

Alternative hypothesis: $\mu > 3.58$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638$

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since is a right tailed test the p value would be:

$p_v =P(t_{(19)}>1.638)=0.0589$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.

7 0

3 years ago

First one: 54 < -9c solve for c<br> Second one: 49> -7a solve for a

Sedbober [7]

Hehsuajs hshshsjisididjisisjisisi

8 0

2 years ago

PLEASE ANSWER QUICKLY!!!!!!!!!!!

Nostrana [21]

21

$\frac{1}{2} height \: of \: trapezium(a + b) = area \: of \: trapezium$

half the height is 3

a=7

b=x

3(7+x)=84

21+3x=84

place the like terms on one side

84-21=3x

63=3x

x=21

3 0

3 years ago