The answer is disposable products.
It has a type of function
A theoretical wind known as the geostrophic wind is produced when the Coriolis effect, as well as the pressure difference forces, are balanced (PGF). It is a decent estimate for the wind reported at middle latitudes at an altitude of greater than 1 km. Given that there is no Coriolis effect near the equator, there can be no geostrophic wind.
What does "geostrophic wind" mean?
Geostrophic flow, as used in atmospheric research, is the fictitious wind that would emerge from a precise balancing act between the Coriolis effect and the pressure difference forces. The term "geostrophic equilibrium" or "geostrophic balance" refers to this situation (also known as geostrophy). Parallel to the isobars is where the geostrophic wind is pointed. In nature, this equilibrium seldom occurs perfectly. Because of these factors, the genuine wind and geostrophic wind nearly never match up.
The location of geostrophic winds:
At elevations exceeding 1000 meters (3300 feet), geostrophic wind can be found. With the use of weather balloons, the geostrophic wind velocity may be calculated. At heights up to 100 meters, the ground surface has a significant impact on winds.
Learn more about the Coriolis effect here:
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Answer: 5. False 6. False
Explanation: The permeases are membrane transport proteins, they're secondary active transporter that allow the movement of a specific molecule in or out of the cell in the direction of a concentration gradient, it is a form of facilitated diffusion and does not require energy. The permease secondary transporter uses the Na ion concentration to move glucose into the cell.
When the ion concentration gradient is set, the concentration of glucose in the cell is higher than the concentration of blood. Glucose will move to the blood by passive diffusion through permease secondary transporter.
The transport mechanism is carrier mediated it does not require energy.
Complete question:
Imagine that a newly discovered, recessively inherited disease is expressed only in individuals with type O blood, although the disease and blood group are independently inherited.
A normal man with type A blood and a normal woman with type B blood have already had one child with the disease. The woman is now pregnant for a second time.
Assuming that both parents are heterozygous for the gene that causes the disease, what is the probability that the second child will also have the disease? Express your answer as a fraction using the slash symbol and no spaces (for example, 1/2).
Answer:
The probability that the second child will also have the disease is 1/16.
Explanation:
<u>Available data:</u>
- Two genes independently inherited: one for blood type, the other for disease
- Man with type A blood x Woman with type B blood
- Both parents are heterozygous for the gene that causes the disease; Dd
If the man has A blood, and the woman has B blood, and they already have an affected child, this means that they must be heterozygous for blood type too.
Cross:
Parentals) AiDd x BiDd
Gametes) AD Ad iD id BD Bd iD id
Punnett square) AD Ad iD id
BD ABDD ABDd BiDD BiDd
Bd ABDd ABdd BiDd Bidd
iD AiDD AiDd iiDD iiDd
id AiDd Aidd iiDd iidd
F1) <u>Genotype</u>:
1/16 ABDD
2/16 ABDd
1/16 ABdd
1/16 AiDD
1/16 BiDD
2/16 AiDd
2/16 BiDd
1/16 Aidd
1/16 Bidd
1/16 iiDD
2/16 iiDd
1/16 iidd
<u>Phenotype:</u>
3/16 A/B normal
4/16 A normal
4/16 B normal
3/16 0 normal
1/16 0 affected by the disease.
