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3 years ago

A rectangular prism has a height of 5 yd and a square base with a side length of 8 yd. What is the surface area of the prism?

1 answer:

5 0

The answer is C, 288 yd and here is why. The formula for the surface area of a rectangular prism is 2(Lw+wh+Lh), with L being the length, w being the width, and h being the height. After that, you plug in your values 2(8(8)+5(8)+5(8)). Make sure you follow PEMDAS, aka The Order of Operations. Solve in the parenthesis first. Inside the parenthesis, it simplifies to 64+40+40, which simplifies to 64+80, which further reduces to 144. Now multiply 144 by 2, which gives you your final answer, 288.

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In a bag are 8 red marbles and 2 blue marbles.What chance does Gracia have of drawing a blue marble in one try without looking?

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she has 1/4 of a chance of drawing a blue marble

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3 years ago

Find the value.<br> X3-4 when x=3<br> PLEASE HELP!!! ASAP!!!

DENIUS [597]

Answer:

Step-by-step explanation:

Raise 3 to the power of 3

27 - 4

Subtract 4 from 27

Hope this was correct

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4 years ago

Read 2 more answers

Many doctors rely on the use of intravenous medication administration in order to achieve an immediate response of a particular

rewona [7]

The domain of the function is 0 ≤ t ≤ 3 and the greatest concentration of the medication is 2mg/L

<h3>The domain of the function</h3>

The equation of the function is given as:

$C(t) = \frac{-18t^2 + 54t}{t^2 + 7t + 10}$

Time can be 0 or greater but cannot be negative.

So, the domain of the function includes t ≥ 0

Set the function to 0 to determine the maximum value of t.

$\frac{-18t^2 + 54t}{t^2 + 7t + 10} = 0$

Cross multiply

$-18t^2 + 54t = 0$

Factor out -18t

-18t(t - 3) = 0

Divide both sides by -18t

t - 3 = 0

Add 3 to both sides

t = 3

This means that the maximum value of t is 3

Hence, the domain of the function is 0 ≤ t ≤ 3

<h3>The greatest concentration of the medication</h3>

From the graph of the function (see attachment), we have the maximum value to be;

C(t) = 2

Hence, the greatest concentration of the medication is 2mg/L

Read more about functions at:

brainly.com/question/1214333

#SPJ1

8 0

2 years ago

Three fractions that can be expressed as percents between 50% and 75%

weeeeeb [17]

1/2,3/4,2/3...................

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4 years ago

Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and th

andrew11 [14]

Answer:

a) 0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b) 0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c) 0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 8.1 minutes and a standard deviation of 2.0 minutes.

This means that $\mu = 8.1, \sigma = 2$

a. between 5 and 10 min

This is the p-value of Z when X = 10 subtracted by the p-value of Z when X = 5.

X = 10

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{10 - 8.1}{2}$

$Z = 0.95$

$Z = 0.95$ has a p-value of 0.8289

X = 5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5 - 8.1}{2}$

$Z = -1.55$

$Z = -1.55$ has a p-value of 0.0606

0.8289 - 0.0606 = 0.7683

0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b. less than 5 min

p-value of Z when X = 5, which, found from item a, is of 0.0606

0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c. more than 10 min

1 subtracted by the p-value of Z when X = 10, which, from item a, is of 0.8289

1 - 0.8289 = 0.1711

0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

7 0

3 years ago