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Burka [1]
3 years ago
14

What are examples of the distributive property?

Mathematics
1 answer:
Elena L [17]3 years ago
8 0
Here is an example:

3(4x +7)
2( 3 +5) =2( 3 ) = 2 ( 5 )
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A swimming pool is 20 feet wide and 40 feet long. If it is surrounded by a walkway of square tiles, each is 1 foot by 1 foot, ho
Lena [83]

Answer:

124 tiles

Step-by-step explanation:

2(20+40)

2(60)

120+4=124

5 0
2 years ago
The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance,
tensa zangetsu [6.8K]

We have the following data set:

2,7,15,3,12,9,15,8,3,10

The range is the difference between the highest and lowest values in the set, to find the range, order the data set from least to greatest.

2,3,3,7,8,9,10,12,15,15

Then,

\begin{gathered} \text{Range}=15-2 \\ \text{Range}=13 \end{gathered}

Mean is represented by the following expression:

\text{Mean}=\frac{\text{Sum of all data points}}{Number\text{ of data po}ints}\text{Mean}=\frac{84}{10}=8.4

Population variance formula looks like this:

\begin{gathered} \sigma^2=\frac{\sum^{}_{}(x-\mu)^2}{N} \\ \text{where,} \\ \sigma^2=\text{population variance} \\ \sum ^{}_{}=addition\text{ of} \\ x=\text{each value} \\ \mu=population\text{ mean} \\ N=\text{ number of values in the population} \end{gathered}

Then, substituting:

\begin{gathered} \sigma^2=\frac{(2-14)^2+(3-14)^2+\cdots+(15-14)^2}{10} \\ \sigma^2=20.44 \end{gathered}

For the standard deviation:

\begin{gathered} s=\sqrt[]{\frac{\sum ^{}_{}(x-\mu)^2}{N}} \\ s=4.521 \end{gathered}

5 0
1 year ago
123 grams is rounded to nearest whole. Write down the minimum possible mass it could have been.
pishuonlain [190]

Answer:

The nearest whole is 122.99 repeated

Step-by-step explanation:

4 0
3 years ago
If the vertex of a parabola is negative for 6 and the other point of the curve is (-3,14) what is the coefficient of the squared
Anton [14]

Answer:

coefficient of the square is a.6

6 0
3 years ago
Bob the builder is making 480kg of concrete mix
vichka [17]

To answer this item, we are first to determine the common factor between the amounts of the cement, sand, and gravel.


If we let x be this factor, the amount of the cement would be x. Similarly, the amount of sand is 3x, and lastly the amount of gravel is 4x. Then, we establish the equation that would let us relate the amounts.


      x + 3x + 4x = 480


Simplifying,

    8x = 480

     x = 60


Hence, the amount of cement is 60 kg, that of sand is 180 kg. Lastly, the amount of gravel is 240 kg. 



5 0
3 years ago
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