Answer: 10, 11, 12
Step-by-step explanation: Think of the integers like this:
1st integer: x
2nd integer: x+1
3rd integer: x+2
That is necessary because they are consecutive integers. Since the sum is 33, we need to create an equation.
x+x+1+x+2=33.
Simplify:
3x+3=33.
Opposite operations:
3x=-3+33.
To get the 3 close to the 33, we needed to make it negative, which is the opposite operation of the positive 3.
So,
3x=30.
Divide by 3:
x=10.
The first integer, x, equals 10.
To go with the guide that we already created,
1st integer: x=10
2nd integer: x+1=11
3rd integer:x+2=12.
Therefore, the three consecutive integers are 10, 11, and 12.
To check that, add them up. They all equal 33 and they are consecutive, which means this is the right answer!
Answer:
B
Step-by-step explanation:
For this problem, let us find the respective speeds of Jasmine and Caroline and compare the two. All we have to do is divide #minutes by #miles to find the time spent per <u>one</u> mile.
Jasmine:

minutes per mile
Caroline:

minutes per mile
Since Caroline takes longer to run a mile than Jasmine, We now know that Jasmine ran at a faster pace:

<u>B. Jasmine ran at a faster pace because she ran 0.3 minutes faster per mile.</u>
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<em>I hope this helps! Let me know if you hae any questions :)</em>
2 IS THE ONLY EVEN PRIME NUMBER a prime number can only be divided by 1 or itself. 4 is a composite and 5 is a prime hope this helps you.
Answer: The initial volume is 593.76mL
Step-by-step explanation:
As you do not say anithing about the pressure, i guess that the pressure remains constant.
If the gas is an ideal gas, we have:
P*V = n*R*T
where P is pressure, n is number of moles and R is a constant.
Now, initially we have:
P*Vi = n*R*315°C
finally we have:
P*825mL = n*R*452°C
Now we can take the quiotient of those two equations and get:
(P*Vi)/(P*852mL) = (n*R*315°C)/( n*R*452°C)
Now we have:
Vi/852mL = 315/452
Vi = (315/452)*852mL = 593.76mL
So when we expand the gas at constant pressure, we increase the temperature.
Answer: d
Step-by-step explanation: