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1 year ago

The graph of the derivative of a function f crosses the x-axis 3 times. What does this tell you about the graph of f ?

Mathematics

2 answers:

expeople1 [14]1 year ago

7 0

Answer:

D. The function f has 3 horizontal tangent lines

Step-by-step explanation:

Well whenever any function crosses the x-axis, it means that the y-value is equal to zero.

In this case when the derivative passes the x-axis it indicates the tangent line corresponding to that x-value has a slope of zero, which when plotted is a horizontal line.

This means that the graph f has 3 horizontal tangent lines.

geniusboy [140]1 year ago

6 0

Answer:

D. The function f has 3 horizontal tangent lines

Step-by-step explanation:

i got 100%

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The first hill on a roller coaster is 155 feet tall. The first drop on a second roller coaster is about 11/20 as tall as the fir

Murljashka [212]

Answer:

85.25

Step-by-step explanation:

155 x (11/20) =85.25 feet

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3 years ago

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A^2+b^2=c^2<br> a^2+10^2=18^2

Papessa [141]

Answer:

$\sqrt[-4]{14}$

Step-by-step explanation:

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2 years ago

The circumference of a circle is 19π m. What is the area, in square meters? Express your answer in terms of \piπ.

lianna [129]

Answer:

90.25π

Step-by-step explanation:

The circumference of circle is 2πr, or in other words the diameter times π.

The area of a circle is πr^2.

19π is the circumference of this circle.

So, 19 is the diameter, and 9.5 the radius.

The area if (9.5^2)π.

9.5^2=90.25

So, in terms of π, the area of the circle is 90.25π.

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2 years ago

I'm lost.. How do you even start it???

Anastasy [175]

$2x+y=4\\
-x+y=1\\\\
2x+y=4\\
\underline{x-y=-1}\\
3x=3\\
x=1\\\\
1-y=-1\\
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3 years ago

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The ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years. Approxima

worty [1.4K]

We have been given that the ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years.

We are asked to find the percentage of students that are between 14 and 18 years old.

First of all, we will find z-score corresponding to 14 and 18 using z-score formula.

$z=\frac{x-\mu}{\sigma}$

$z=\frac{14-15}{2}$

$z=\frac{-1}{2}$

$z=-0.5$

Similarly, we will find the z-score corresponding to 18.

$z=\frac{18-15}{2}$

$z=\frac{3}{2}$

$z=1.5$

Now we will find the probability of getting a z-score between $-0.5$ and $1.5$ that is $P(-0.5$ .

$P(-0.5$

Using normal distribution table, we will get:

$P(-0.5$

Let us convert $0.62465$ into percentage.

$0.62465\times 100\%=62.465\%\approx 62.5\%$

Therefore, approximately $62.5\%$ of the students are between 14 and 18 years old.

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2 years ago

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