The five interior angles in a pentagon are in the ratio 2:3:4:5:6. What is the measure of the pentagon's largest angle?
1 answer:
Let All angles be x times multiplied to ratio , so we"ll get :-
2x + 3x + 4x + 5x + 6x = 540°
20x = 540
x = 540/20
⇒ x = 27 ,
so angles are :-
⇒ 2x = 2×27 = 54°
⇒ 3x = 3×27 = 81°
⇒ 4x = 4×27 = 108°
⇒ 5x = 5×27 = 135°
⇒ 6x = 6×27 = 162°
Hence 162° is the greatest angle
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