Answer:converge at 
Step-by-step explanation:
Given
Improper Integral I is given as

integration of
is -
![I=\left [ -\frac{1}{x}\right ]^{\infty}_3](https://tex.z-dn.net/?f=I%3D%5Cleft%20%5B%20-%5Cfrac%7B1%7D%7Bx%7D%5Cright%20%5D%5E%7B%5Cinfty%7D_3)
substituting value
![I=-\left [ \frac{1}{\infty }-\frac{1}{3}\right ]](https://tex.z-dn.net/?f=I%3D-%5Cleft%20%5B%20%5Cfrac%7B1%7D%7B%5Cinfty%20%7D-%5Cfrac%7B1%7D%7B3%7D%5Cright%20%5D)
![I=-\left [ 0-\frac{1}{3}\right ]](https://tex.z-dn.net/?f=I%3D-%5Cleft%20%5B%200-%5Cfrac%7B1%7D%7B3%7D%5Cright%20%5D)

so the value of integral converges at 
No. If you do 6+1/3 and 24+1/3 it is not equal.
Answer:
The nth term of the geometric sequence 7, 14, 28, ... is:

Step-by-step explanation:
Given the geometric sequence
7, 14, 28, ...
We know that a geometric sequence has a constant ratio 'r' and is defined by

where a₁ is the first term and r is the common ratio
Computing the ratios of all the adjacent terms

The ratio of all the adjacent terms is the same and equal to

now substituting r = 2 and a₁ = 7 in the nth term


Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

The answer for ure question is x<-1/2
plse mark me brainliest
Answer:he has the wrong unit
Step-by-step explanation:
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Ght