Answers:
1. 1
2. 2
3. 4
4. 1
//Hope this helps. Look the image for better understanding.
We know that:
∠ABC=∠BCA=xº
∠BDC=∠BCD=xº
1) we have to find the angle ∠DBC:
∠BDC+∠BCD+∠DBC=180º
xº+xº+∠DBC=180º
2xº+∠DBC=180º
∠DBC=180º-2xº
2) we have to find the angle ∠ABD:
∠ABD=∠ABC-∠DBC
∠ABD=xº-(180º-2x)
∠ABD=xº-180º+2xº
∠ABD=3xº-180º
Answer: ∠ABD=3xº-180º
16+64=80 80*2=160
or it means
64/2=32 32+16= 48
or it means
64+16=80 80/2= 40
this is a horribly formatted question
Sorry, can not see the full picture, try uploading the full image of the question.