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Otrada [13]
3 years ago
9

Mila has 100 math problems to finish this week. She solved 2/10 of the problems on monday and 25/100 on tuesday. Which day did s

he solve more problems?
Mathematics
2 answers:
dem82 [27]3 years ago
7 0
Tuesday was the day.
Archy [21]3 years ago
4 0
Tuseday because 25/100 in decimal form is .25 and 2/10 in decimal form is .2
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Need help with these!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Gelneren [198K]

Answer:

Step-by-step explanation:

8 0
3 years ago
Can someone help me with this! I don’t understand
Maru [420]

Answer:

B

Step-by-step explanation:

We are given:

y=4x

2x^2-y=0

We are going to put 4x in place of the second y since the first y equaled it:

2x^2-4x=0

So we can factored this equation:

2x(x-2)=0

This implies 2x=0 or x-2=0.

2x=0

Divide both sides by 2:

x=0

x-2=0

Add 2 on both sides:

x=2

If x=0 and y=4x, then y=4(0)=0 so we have (0,0) is an intersection.

If x=2 and y=4x, then y=4(2)=8 so we have (2,8) is an intersection.

7 0
3 years ago
Read 2 more answers
Choose the expression that correctly compares 4.152 and 4.25.<br> 4.152 = 4.25<br> 4.152 4.25
BlackZzzverrR [31]
4.25 is greater than 4.152. therefore they aren’t equal
5 0
3 years ago
Read 2 more answers
Line segment EF has a length of 5 units. It is translated 5 units to the right on a coordinate plane to obtain line segment E′F′
Dimas [21]

Answer 25 units

Step-by-step explanation:

cause there are already 5 so multipy 5

3 0
3 years ago
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Suppose that D(r) is a function which gives the population density, in hundreds of people per square mile, within r miles of the
borishaifa [10]

Answer:

a) T(r) = r.D(r)

b) 975 people per square mile.

Step-by-step explanation:

(a)

The units of D(r) are  

\frac{hundreds\;of\;people}{mile^2}

when multiplying the density by the area we get the amount of people in that area, so

T(r)=rmile^2D(r)\frac{hundreds\;of\;people}{mile^2}=rD(r)\;hundreds\;of\;people

(b)

The average rate of change of T(r) over the interval [5,7] is

\frac{T(7)-T(5)}{7-5}=\frac{7D(7)-5D(5)}{2}

but D(7) = 350 and D(5) = 100, so

\frac{7D(7)-5D(5)}{2}=\frac{7*350-5*100}{2}=975

and the average rate of change of T(r) over the interval [5,7] is 975 people per square mile.

5 0
4 years ago
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