Question

Can someone help me with this! I don’t understand

Answer 1

Answer:

B

Step-by-step explanation:

We are given:

$y=4x$

$2x^2-y=0$

We are going to put 4x in place of the second y since the first y equaled it:

$2x^2-4x=0$

So we can factored this equation:

$2x(x-2)=0$

This implies 2x=0 or x-2=0.

2x=0

Divide both sides by 2:

x=0

x-2=0

Add 2 on both sides:

x=2

If x=0 and y=4x, then y=4(0)=0 so we have (0,0) is an intersection.

If x=2 and y=4x, then y=4(2)=8 so we have (2,8) is an intersection.

Answer 2

Answer:

the answer to the problem given is b