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NeX [460]
2 years ago
5

Lori wants to spend less than $20 on her school lunches this week. If she plans to buy all her lunches at school this week, on a

verage, how much can she spend in a day?
Inequality:
Mathematics
1 answer:
Elden [556K]2 years ago
8 0

Answer:

average = amount/ days

the answer is 4

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55 more than a number is twenty.
Mrac [35]

Answer:-35

Step-by-step explanation:

To find 55 more a number equal to 20

We get

Let the number b y

55 more than the number

We be

y+55=20

y=20-55

y=-35

7 0
3 years ago
What the recursive formula for the sequence
klemol [59]

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a_n=2-5(n-1)\implies a_n=\stackrel{\stackrel{a_1}{\downarrow }}{2}+(n-1)(\stackrel{\stackrel{d}{\downarrow }}{-5})


so, we know the first term is 2, whilst the common difference is -5, therefore, that means, to get the next term, we subtract 5, or we "add -5" to the current term.

\bf \begin{cases} a_1=2\\ a_n=a_{n-1}-5 \end{cases}


just a quick note on notation:

\bf \stackrel{\stackrel{\textit{current term}}{\downarrow }}{a_n}\qquad \qquad \stackrel{\stackrel{\textit{the term before it}}{\downarrow }}{a_{n-1}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{current term}}{a_5}\qquad \quad \stackrel{\textit{term before it}}{a_{5-1}\implies a_4}~\hspace{5em}\stackrel{\textit{current term}}{a_{12}}\qquad \quad \stackrel{\textit{term before it}}{a_{12-1}\implies a_{11}}

8 0
3 years ago
Answer this quickly plx​
Natalija [7]

Answer:

10x+200\leq375

Step-by-step explanation:

subtract 200 from both sides

10x\leq175

divide both sides by 10

x\leq17.5 cars

Jesse must wash atleast 17.5 cars to afford the bike.

5 0
3 years ago
About how much farther is it to drive than to walk directly from building A to building B? Round to the nearest whole number.
Sav [38]

Answer:

A. 183 meters

Step-by-step explanation:

Building A and building B are 500 meters apart. There is no road between them, so to drive from building A to building B, it is necessary to first drive to building C and then to building B. About how much farther is it to drive than to walk directly from building A to building B? Round to the nearest whole number. A) 183 meters B) 250 meters C) 366 meters D) 683 meters

Find distance BC

Cos (60°)=BC / AB (Adjacent divided by the hypotenuse)

Cos (60°)=1/2

BC=a

AB=500

Cos (60°)=BC / AB

1/2=a/500

1/2 * 500=a

250=a

a=250m

Find distance AC

Sin(60°)=AC/AB (opposite side divided by hypotenuse)

Sin(60°)=√3/2

AC=b

AB=500

Sin(60°)=AC/AB

√3/2=b/500

√3/2 * 500=b

250√3=b

b=433m

Distance AC and BC=AC+BC

433m+250m=683m

Subtract the distance AB from AC+BC

= 683m - 500m

=183m

Answer is A. 183 meters

8 0
3 years ago
Which features are correctly stated? There is more than one answer.
ahrayia [7]
Hope this helps-

y= (x+2)2-3

4 0
3 years ago
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