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Mathematics

1 answer:

Andrew [12]3 years ago

8 0

Answer:(2.2).

Step-by-step explanation:

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What is the equation for the hyperbola shown?

castortr0y [4]

Answer:

$\frac{x^{2} }{3600} - \frac{y^{2} }{121} = 1$

Step-by-step explanation:

Since the hyperbola opens left and right with a center at the origin, then

$\frac{x^{2} }{^{2} } - \frac{y^{2} }{b^{2} } = 1$

In the graph a = 60 and b = 11

$\frac{x^{2} }{60^{2} } - \frac{y^{2} }{11^{2} } = 1$ .

$\frac{x^{2} }{3600} - \frac{y^{2} }{121} = 1$

7 0

2 years ago

8p+8=10+7p what is the solution set

Evgesh-ka [11]

The answer is: "p = 2" .
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Explanation:
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Given:
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" 8p + 8 = 10 + 7p " ; Solve for "p" ;

Subtract "7p" from each side of the equation; & subtract "8" from each side of the equation; as follows:

8p + 8 − 7p − 8 = 10 + 7p − 7p <span>− 8 ;
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to get:
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"p = 2 " ; which is our answer.
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8 0

3 years ago

Read 2 more answers

Actually thats wrong bc my teacher did it with us but i really dont know the answer

Dvinal [7]

Answer:

???

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

In f(x) = 2x2 − 8x − 10, the y-intercept is ? at ? and the x-intercepts are (-1, 0) and ? .

IgorLugansk [536]

<h2>1. y-intercept</h2>

$\boxed{(0,-10)}$

The quadratic function $f(x)=2x^22-8x-10$ represents a parabola. In fact, the graph of a quadratic function is a special type of U-shaped curve called a parabola. To find the y intercept, we set $x=0$ as follows:

$f(x)=2x^2-8x-10 \\ \\ If \ x=0 \rightarrow f(0)=-10 \\ \\ Then \ y-intercept: \\ \\ (0,-10)$

<h2>2. x-intercepts</h2>

$\boxed{(-1,0) \ and \ (5,0)}$

To find the other x-intercept, we must set $y=0$ as follows:

$f(x)=2x^2-8x-10 \\ \\ If \ y=0 \rightarrow 2x^2-8x-10=0 \\ \\ Using \ the \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \therefore x=\frac{-(-8) \pm \sqrt{(-b)^2-4(2)(-10)}}{2(2)} \\ \\ \therefore x_{1}=-1 \ and \ x_{2}=5$