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3 years ago

CD is an altitude of ACB. What is the length of AD? ОА. 10 ОВ. 20 OC. 12 OD. 11

Mathematics

1 answer:

Simora [160]3 years ago

7 0

Answer:

D. 11

CD is half the length of DB

Triangle ACD must be proportional to Triangle BCD

AD must be half the length of CD

Therefor, your answer is 11.

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Evaluate lim x approaches to 2 : (sqrt(6-x)-2)/(sqrt(3-x)-1)

solong [7]

Answer:

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Step-by-step explanation:

Given:

$\to \lim_{x\to 2} \frac{(\sqrt{(6-x)}-2)}{(\sqrt{(3-x)}-1)}\\\\ \to \lim_{x\to 2} \frac{\frac{d(\sqrt{(6-x)}-2)}{dx}}{\frac{(\sqrt{(3-x)}-1)}{dx}}\\\\$

$\to \lim_{x\to 2} \frac{\frac{-1}{2\sqrt{(6-x)} }}{\frac{-1}{2\sqrt{(3-x)}}}\\\\$

$\to \lim_{x\to 2} \frac{\sqrt{3-x}}{\sqrt{6-x}}\\\\ \to \frac{\sqrt{3-2}}{\sqrt{6-2}}\\\\ \to \frac{\sqrt{1}} {\sqrt{4}}\\\\ \to \frac{1}{2}\\\\ \to 0.5$

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Answer:

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Step-by-step explanation:

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