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3 years ago

Solve for x in the literal equation −3 = xy + z.

2 answers:

7 0

- 3 = xy + z

xy + z = - 3

subtract z from both sides:

xy +z - z = -3 - z

yx = - 3 - z

Divide both sides by y :

yx / y = - 3 - z / y

x = -3-z / y

y ≠ 0

hope this helps!

dimaraw [331]3 years ago

3 0

Answer:

-3-z/y please mark brainliest

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3 4 x + 6 = 1 + 1 3 x

torisob [31]

Answer:

$\boxed{x = -5/21}$

Step-by-step explanation:

Hey there!

To simplify we need to combine like terms and use the communicative property,

34x + 6 = 1 + 13x

-13x to both sides

21x + 6 = 1

-6 to both sides

21x = -5

Divide both sides by 21

x = -5/21

Hope this helps :)

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3 years ago

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Reggie,Alvin, and Jose are member of a relay running team. Reggie finished his leg of the race 2.45 seconds faster than Alvin an

user100 [1]

If R represents Reggie's time, the total time for the team is
.. R +(R +2.45) +(R -3.81) = 3R -1.36
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4 years ago

Lines j and k are parallel how to solve

Ede4ka [16]

I can't answer your question without a picture... Sorry.

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3 years ago

How do you solve 1/x + 1/y + 1/z = 1 for z?

garri49 [273]

Answer:

$\large\boxed{z=\dfrac{xy}{xy-x-y}}$

Step-by-step explanation:

$\dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{z}=1\qquad\text{multiply both sides by}\ xyz\neq0\\\\xyz\cdot\dfrac{1}{x}+xyz\cdot\dfrac{1}{y}+xyz\cdot\dfrac{1}{z}=xyz\cdot1\qquad\text{simplify}\\\\yz+xz+xy=xyz\qquad\text{subtract}\ xy\ \text{from both sides}\\\\xz+yz=xyz-xy\qquad\text{subtract}\ xyz\ \text{from both sides}\\\\xz+yz-xyz=-xy\qquad\text{distribute}\\\\(x+y-xy)z=-xy\qquad\text{divide both sides by}\ (x+y-xy)\\\\z=\dfrac{-xy}{x+y-xy}\\\\z=\dfrac{-xy}{-(xy-x-y)}\\\\z=\dfrac{xy}{xy-x-y}$

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3 years ago

Mr. Randall bought 4 shirts, which were on sale. The shirts were originally priced $20 The sales price of the shirts was $5 less

Leona [35]

$20 x 4 shirts = $ 80

But less $5 foreach one $5 × 4 = 20

So net money paid $80 - $20 = $60 ans

Mark as 5 star plzzz

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4 years ago

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