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Sedbober [7]
3 years ago
10

Can someone help me solve this, show work if you can.

Mathematics
1 answer:
solmaris [256]3 years ago
7 0

um what

sory not understand from finland good luck

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Simplify the expression<br> -4x – 7+3 – 8x
julia-pushkina [17]

Answer:

-12x - 4

Step-by-step explanation:

if you can please mark brainlyist

5 0
2 years ago
Read 2 more answers
Dustin has only nickels and quarters in his piggy bank. He has 49 coins total for a combined value of $8.85. How many of each ty
eduard
Well obviously quarters equal 25 cents.  So you have to divide the 8.85 by 25 first.  That means he could have 35 quarters.  That least the rest as being dimes.  So find the remaining amount of the 8.85.  If you have 35 quarters that's $8.75.  And 8.85 minus 8.75 is 10 cents.  which would be 2 nickels.  That only adds up 37 coins.  So you break down one of the 25.  That would mean 5 more coins could be nickels.  Add 37 and 5 to get 42.   Do it again.  25 cents in nickels would be 5 more coins.  would be 46.  that would be missing 2 coins. But don't forget you're also subtracting from the 35 quarters. Now you would technically have 12 nickels and 33 quarters.  So you can do it one more time.  32 quarters means there is $8 in quarters at this point.

Now add you have 12 nickels, and you made 5 more.  That's 17 nickels.  That equals 85 cents.  So add 17 and 32 to be sure you have 49 coins, which you do. 


So 17 nickels, 32 quarters to equal 49 coins and $8.85

(sorry some of it got mixed up above because I was forgetting to subtract the quarters from the total as I changed them to nickels, so pay attention to the end)
8 0
3 years ago
Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0
3 years ago
Plz help asap real quick i will put you as brainlist
professor190 [17]

Answer:

21/8*2= 5 2/8 or 5 1/4

Step-by-step explanation:

Divide fraction so keep change flip

make them improper

21/8 * 2

42/8

5 2/8

5 1/4

3 0
3 years ago
Read 2 more answers
Algebra problem, please show work!
Brrunno [24]

6x+1 / 2x +6 - 5/2

Factor 2 out of the denominator of the first fraction:

6x+1 / 2(x+3) - 5/2

Rewrite 5/2 to have a common denominator with the first fraction:

6x+1/2(x+3) - 5(x+3) / 2(x+3)

Simplify terms:

6x +1 - 5(x+3) / 2(x+3)

Use distributive property:

6x +1 - 5x -15 / 2(x+3)

Combine like terms for final answer:

(x-14) / 2(x+3)

4 0
3 years ago
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