Answer:
Hi What is the perimeter of this polygon?
A
−11f−8d−11
B
−f+5d−3d−3f
C
f−3+6d
D
2d−4fWhat is the perimeter of this polygon?
A
−11f−8d−11
B
−f+5d−3d−3f
C
f−3+6d
D
2d−4f
Explanation:
The second that they when on the dry door how they could be two part again it so I tomho that on how there
A and B i think am not sure
Answer:
A. 21 rad/s
B. 200.5 rpm
C. 26.46 rad/s2
D. 0.299 Hz
Explanation:
Parameters given are:
Tangential velocity,v = 1.26m/s
Diameter (outer edge) = 0.120m
Outer edge radius, ro = 0.12/2
= 0.06m
A. Calculate Angular velocity
Angular velocity, w = v/r
= v/ro
= 1.26/0.06 = 21 rad/s
In rpm,
2pi/60 rad/s = 1 rpm
1 rad/s = 60/2pi rpm
Sp, 21 rad/s = 60 * 21/2pi rpm
= 200.5 rpm
B. Calculate the inner edge radius, ri given w = 500 rpm
Converting rpm to rad/s,
= 2pi/60 * 500 rad/s
= 52.34 rad/s
ri = v/w
= 1.26/ 52.36
= 0.024m
C. Calculating centripetal acceleration, a from the outer edge, ro
a = v2/r = w2r
= (1.26)2/0.06
= 26.46 rad/s
D. Calculate the frequency, f of the outer edge angular velocity, w = 21 rad/s
f = 2pi/w
= 2pi/21
= 0.299 Hz (or per second)
An immediate corollary for the special case of uniform motion is that Newtonian physics is inconsistent with his first law and is, instead, consistent with Galileo's definition of inertial motion.
Hope this helpsss!!!! :)))))
