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andreyandreev [35.5K]
4 years ago
14

Round seeds (R) are dominant to wrinkled seeds (r), and yellow seeds (Y) are dominant to green seeds (y). What is the expected p

henotypic ratio of a cross between an RrYy and an rryy individual?

Biology
1 answer:
asambeis [7]4 years ago
3 0

Answer:

The correct answer would be- 1:1:1:1.

Explanation:

According to the question the cross between the two pea plants with the genotype RrYy and rryy where R for round seeds and r for recessive form that expressed wrinkled seed character. The other character of this dihybrid cross is the color of the seds Y for green and y for yellow seeds.

The cross is shown in the image attached that suggests that phenotypic ratio would be 1:1:1:1 as RrYy, Rryy, rrYy, and rryy.

Thus, the correct answer is : 1:1:1:1.

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According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the alleles. The genotypic frequencies after one generation are p² (Homozygous for allele p), 2pq (Heterozygous), q² (Homozygous for the allele q). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.

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