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kap26 [50]
3 years ago
15

Picture attached! help please!

Chemistry
1 answer:
PolarNik [594]3 years ago
6 0
Answer 31 is the letter B
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calculate the concentration in parts per million (ppm) of DDT if a sample size of 2000 g contained 0.050 g DDT
Firlakuza [10]

Answer:

= 25 ppm

Explanation:

  • PPM also refers to parts per million, it represents a low concentration of a solution. It represents 0.001 gram or a milligram in a 1000 mL, which equivalent to 1 mg per liter.

Given; a sample size of 2000 g contained 0.050 g DDT

It means, 2000 mL sample contained 50 mg DDT

Therefore in ppm we get;

= 50 mg/ 2 L

= 25 mg/L

<u>= 25 ppm</u>

4 0
3 years ago
You are on vacation with your family up in the mountains. your friend is on vacation near the equator by the ocean.Explain which
kirill115 [55]

Answer:

option d is right

Explanation:

More precipitation occurs near the equator because it is a tropical area. Mountains receive less than 15 inches of rain per year while the equator area receives a lot of rain. This is due to the very hot weather.

8 0
3 years ago
Convert 25 km to mm.
nalin [4]

Answer:

25000000 millimeters

Explanation:

4 0
3 years ago
Read 2 more answers
If an old car burns 0.05 mL oil every mile, How much oil will it burn if driven 100,000 miles? Show your answer in mL and L?.
Irina18 [472]

0.05 * 100000

= 5000ml

= 5L

7 0
3 years ago
A solution contains 1.817 mg of CoSO4 (155.0 grams/mole) per mL. Calculate the volume (in mL) of 0.009795 M Zn2 needed to titrat
Nana76 [90]

Answer:

<u> </u><u>85.952 ml</u> Zn^2^+  needed to titrate the excess complexing reagent .

Explanation:

Lets calculate

After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml

As the number of moles of CoSO_4 =\frac{Given mass }{molar mass}

                                                       =\frac{1.817}{155}

                                                          =0.01172

Molarity = \frac{no. of moles}{volume of solution}

           =\frac{0.01172}{20}

        =0.000586 moles

Excess of EDTA = concentration of EDTA - concentration of CoSO4

                            = 0.009005 - 0.000586

                           = 0.008419 M

As M1V1 ( Excess of EDTA ) = M2V2 (Zn^2^+)

           0.008419\times100ml=0.009795\times V2

           V2=\frac{0.008419\times100}{0.009795}

             V2 =85.952 ml

Therefore , <u>85.952 ml </u>Zn^2^+ needed to titrate the excess complexing reagent .

3 0
3 years ago
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