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Anvisha [2.4K]
3 years ago
15

What are the constant terms in the expression? 13xyz+4+2z+5 out of these 13,13xyz,x, y, z,4,2,5

Mathematics
1 answer:
Kruka [31]3 years ago
7 0
Constant terms are 4 and 5
13xyz is not because it is dependent on what x,y, and z 
and 2z the same thing
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Find the domain and range of the relation.<br> {(3,-2) (2,1) (-1,0) (1,3)}
svp [43]
The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.
5 0
2 years ago
Is y =3/4x +2 And -6x+8y=16 parallel or coincident
Rudiy27

Answer:

parallel

Step-by-step explanation:

y=3/4x+2

Multiply the equation by 8:

8y=6x+16

(8y-6x)=16

and you can clearly see that they're same

4 0
3 years ago
which of the following best describes the technique used to graph the equation using the slope and y-intercept ? Y=5x+10
Vinvika [58]
The slope-intercept is y = mx+b. You can use this as a technique for graphing to make the experience easier. The "5" would be the slope or rise/run of the line. The 10 would be where it started on the y-intercept. You could also say it would be (0,10). Since the slope is positive than it would be going in an upward direction. That is why this technique is good for graphing. I hope this helps you and please put me as the brainliest answer. :)
5 0
3 years ago
Read 2 more answers
On the 1st January 2014 Carol invested some money in a bank account.
Ghella [55]

Answer:

\large \boxed{\text{\pounds 23 360.00}}

Step-by-step explanation:

The formula for the accrued amount from compound interest is

A = P \left(1 + \dfrac{r}{n}\right)^{nt}

1. Amount in account on 1 Jan 2015

(a) Data:

a = £23 517.60

r = 2.5 %

n = 1

t = 1 yr

(b) Calculations:  

r = 0.025

\begin{array}{rcl}23517.60 & = & P\left (1 + \dfrac{r}{n}\right)^{nt}\\\\& = & P\left (1 + \dfrac{0.025}{1}\right)^{1\times1}\\\\& = & P (1 + 0.025)\\ & = & 1.025 P\\P & = & \dfrac{23517.60 }{1.025} \\\\& = & 22 944.00 \\\end{array}

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.

She must have had £23 944 in her account on 1 Jan 2015.

(2) Amount originally invested

(a) Data

A = £23 944.00

\begin{array}{rcl}23 944.00 & = & 1.025 P\\P & = & \dfrac{23 944.00 }{1.025} \\\\& = & \mathbf{23 360.00} \\\end{array}\\\text{Carol originally invested $\large \boxed{\textbf{\pounds23 360.00}}$ in her account.}

3. Summary

1 Jan 2014      P = £23 360.00

1 Jan 2015     A =    23 944.00

     Withdrawal = <u>    -1  000.00 </u>

                     P =     22 944.00

1 Jan 2016    A =    £23 517.60

5 0
3 years ago
Suppose that, in 1995, Germany produced 4.719 million computers. The total world production that year totaled 80 million compute
Reptile [31]

Answer:

To the nearest tenth

Percentage= 5.9%

Step-by-step explanation:

In 1995, Germany produced 4.719 million computers.

In that same year, the total computer production of the whole world was 80 million.

The percentage of the world production contributed by Germany

=Number produced by Germany/Number produced by the whole world * 100

The percentage of the world production contributed by Germany

=( 4.719/80)*100

The percentage of the world production contributed by Germany

=5.89875%

To the nearest tenth

= 5.9%

3 0
3 years ago
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