All categories

3 years ago

What are the constant terms in the expression? 13xyz+4+2z+5 out of these 13,13xyz,x, y, z,4,2,5

Mathematics

1 answer:

Kruka [31]3 years ago

7 0

Constant terms are 4 and 5
13xyz is not because it is dependent on what x,y, and z
and 2z the same thing

You might be interested in

What statement is NOT true about the pattern shown below? 2/3, 4/6, 8/12, 16/24 Choices: Each fraction is greater than the previ

-Dominant- [34]

Answer: Each fraction is greater than the previous fraction.

Step-by-step explanation:

The fractions given are:

2/3, 4/6, 8/12, 16/24

Note that

2/3 = 4/6 = 8/12 = 16/32

The Fractions are all equal. Each fraction is equivalent to 2/3

The pattern used here is:

2/3 × 2/2 = 4/6

4/6 × 2/2 = 8/12

8/12 × 2/2 = 16/24

16/24 × 2/2 = 32/48

Each fraction is equal to the previous fraction in the pattern multiplied by 2/2

Also, the next fraction in the pattern is 32/48.

The statement that "Each fraction is greater than the previous fraction" is incorrect. The fractions are all equal.

4 0

3 years ago

For the function given state the period f(t) =6sin(3t-pi/6)-1

lapo4ka [179]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's take a peek at yours

$\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}$

8 0

4 years ago

Select the procedure that can be used to show the converse of the Pythagorean theorem using side links chosen from 3 feet, 4 fee

snow_tiger [21]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which of the following lowers the total monthly payment on a vehicle, and is generally offered by the dealership? Apex

Georgia [21]

money towards a down payment

5 0

3 years ago

Read 2 more answers

Astrid is in charge of building a new fleet of ships. Each ship requires 40 tons of wood, and accommodates 300 sailors. She rece

gogolik [260]

Answer:Astrid needs 280 tons of wood

Step-by-step explanation:

Because:

1 ship requires 40 tons of wood=accomodates 300 sailors

We must:

2100, sailors needed to be accomodated

300, sailors that can be accomodated by 1 ship that requires 40 tons of wood

=7 groups of 300 sailors that can be accomodated by 1 ship that requires 40 tons of wood.

So:

I ship that requires 40 tons of wood × the 7, groups = 280 tons of wood.

I hope this helps! Im sorry its too complicated.

Simplier:

2100 ÷ 300= 7

40 × 7= 280

6 0

4 years ago