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3 years ago

Help! 20 points svhs

Mathematics

2 answers:

statuscvo [17]3 years ago

8 0

Answer:

Step-by-step explanation:

First add all your like terms.

52a - 25 = 79

Add 25 to both sides to cancel the 25 and isolate the variable.

52a = 104

Divide both sides by to find a.

a = 104/52

a = 2

zepelin [54]3 years ago

5 0

Answer:

d. 2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

45a−25+7a=79

45a+−25+7a=79

(45a+7a)+(−25)=79(Combine Like Terms)

52a+−25=79

52a−25=79

Step 2: Add 25 to both sides.

52a−25+25=79+25

52a=104

Step 3: Divide both sides by 52.

52a

104

a=2

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Answer:

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Step-by-step explanation:

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2 years ago

The sum of a number and three is doubled and then added to the product of six and the original number to give forty six

Zina [86]

Answer:

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Step-by-step explanation:

Let x represent the number

Now let's break it down!

Sum of a number and 3 gives;

x + 3

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3 years ago

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Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

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