1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Diano4ka-milaya [45]
3 years ago
5

What is the relationship between the 6s in 660,472

Mathematics
2 answers:
jek_recluse [69]3 years ago
6 0

Answer:

The relation between the 6s in 660,472 is one 6 is at hundred thousand place and the second 6 at ten thousands place.

Step-by-step explanation:

Consider the provided number 660,472

According to place value the number can be written as:

Hundred Th.    Ten Th.   Thousands   hundreds   Tens   Ones

  600,000         60,000       -----              400            70        2

We need to find the relationship between the 6s.

Here, we can see that the first 6 from the right is at hundred thousands place and the second 6 from the right is at the ten thousands place.

That means the first 6 is 10 times greater than the second 6.

Hence, the relation between the 6s in 660,472 is one 6 is at hundred thousand place and the second 6 at ten thousands place.

ser-zykov [4K]3 years ago
5 0
They have two different place values one 6 is in ten thousands place the other is in the hundred thousands place
You might be interested in
Plz help me ...
Novay_Z [31]
  • 10kg=390 Rs
  • 100kg=4 000 Rs
  • 390x10= 3900 rs
  • 4000-3900=100 Rs
  • lỗ 100rs
8 0
3 years ago
Point A is located at -5/8 and point B is located at -2/8. What is the distance between points A and B
UNO [17]
I think those are coordinates of points, (-5,8) and (-2,8)
so you just need to use distance formula ((8-8)^2+(-2+5)^2)=0+9=9
square root 9=3
3 0
3 years ago
How many ways can you give 18 cards to 2 people
NeTakaya
9 because 18÷2=9
you can use models to help too
get 18 things and put them in 2 groups
3 0
3 years ago
Read 2 more answers
suppose the distnace in feet that an object travels t seconds is given by the formula d=64t^2 how far would the object travel af
Darya [45]

Answer:

The object travels 144,000,000 feet.

Step-by-step explanation:

The distance the object travel after t seconds is given by:

d(t) = 64t^2

How far would the object travel after 1.5 * 10^3 seconds

This is d when t = 1.5 \times 10^3 = 1500, so d(1500)

d(1500) = 64*1500^2 = 144000000

The object travels 144,000,000 feet.

8 0
3 years ago
30 POINTS!! Write the slope-intercept form of the equation for the line.
Anton [14]

Answer:

B. y = -\frac{3}{10}x + \frac{1}{2}

Step-by-step explanation:

Well slope-intercept form is y = ax + b.

Let's start with the slope.

In this case, finding the slope is easy.

It should have a negative slope.

So we can cross out answer choices A. and C.

Also, we can cross out D. because it just makes no sense, -10/3, if you start from the y-intercept and go down 10 and across 3, yeah that's

not the slope.

So we can cross out D.

The only answer choice left is B.

We can tell the y-intercept is 1/2 because like come on so B is the correct answer.

B. y = -\frac{3}{10}x + \frac{1}{2}

8 0
3 years ago
Read 2 more answers
Other questions:
  • Determine if the relation represents a function. Explain
    7·1 answer
  • Joshua drew a triangle. the first angle measured 35, the second angle measured 100, and the third measured 45. what type of tria
    8·1 answer
  • Pls help!!!!!!! Determine the lowest common denominator for each sum or difference.
    10·1 answer
  • Please help worth 25 points
    9·1 answer
  • Plz help! will give brainliest!!!
    5·1 answer
  • How do I know if the function is a linear function?
    14·1 answer
  • Help please I don’t know the answer and I’m like late soo
    12·2 answers
  • 3 equivalent rations of 3 : 11
    14·1 answer
  • Please help!! thanks!
    10·1 answer
  • Come up with two examples of ratio relationships that are interesting to you.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!