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Gnesinka [82]
3 years ago
15

"The major driving forces of behavior are learning and rewards."

Biology
2 answers:
Fantom [35]3 years ago
7 0

Answer: The correct answer for the blank is -

comparative behaviorist.

Explanation:

Comparative psychology can be described as the scientific study of the behavior and mental processes, particularly relating to the development of behavior (which is drived by rewards and learning), adaptive significance, and phylogenetic history of organisms.

Comparative behaviorist are the researchers that are devoted for such work.

Thus, the given statement, "The major driving forces of behavior are learning and rewards" is made by a comparative behaviorist.

ankoles [38]3 years ago
3 0
A comparative behaviorist
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Why is the alpine tundra important to protect
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Answer: the tundra is important to protect is that it serves as a habitat for migratory populations, like waterfowl, shorebirds, caribou and several bear species. It is home to endangered animals such as the Arctic Fox, Polar Bear, Grizzly Bear, Caribou, and Musk Ox.

Explanation:

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3 years ago
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What type of cells, sex cells or somatic cells ,are produced by this process
pogonyaev

Answer:

Human sex cells are produced by a two-part cell division process called meiosis.

Explanation:

Through a sequence of steps, the replicated genetic material in a parent cell is distributed among four daughter cells. Meiosis produces gametes with one-half the number of chromosomes as the parent cell

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3 years ago
You are a botanist looking at the plant color in a new breed of Snapdragon. The two parent plants are Blue and Green and when yo
irakobra [83]

Answer:

Incomplete dominance is the inheritance pattern where the dominant allele did not mask the recessive allele completely and form a mix of both alleles. Here the inheritance is the incomplete inheritance. The ratio of F2 generation is 1:2:1.

Given:

R1R1 = 42

R2R2 = 39

R1R2 = 86

Total R1 alleles = 2*42+86 = 170

Total R2 alleles = 2*39+86 = 164

Total alleles = 334

Frequency of allele R1 = 170/334 = 0.51

Frequency of allele R2 = 164 / 334 = 0.49

Expected number of each phenotype:

Total population = 167

Blue = R1R1 = 0.51 * 0.51 * 167 = 43.44

Green = R2R2 = 0.49 * 0.49 * 167 = 40.10

Cyan = 2*R1*R2 = 2*0.51*0.49*167 = 83.46

Phenotype     Observed(O)    Expected (E)    O-E      (O-E)2     (O-E)2/E

Blue                 42                   43.44               -1.44       2.0736     0.0477

cyan                86                   83.46                 2.54     6.4516     0.0773

green              39                    40.1                    -1.1       1.2100      0.0302

Total              167                     167                                               0.1552

Chi-square value = 0.155

Degrees of freedom = no. of phenotypes – 1

Df = 3-1 = 2

Critical value = 5.99

Chi-square value of 0.155 is less than the critical value of 5.99. So we accept the null hypothesis.

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the 3rd one

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