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Reil [10]
3 years ago
12

What is the fraction of this problem

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
7 0

Answer:

7/10

Step by Step Explanation:

there are 10 parts and 7 parts shaded.

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Find the area of a circle with a radius of 6 centimeters. Round to the nearest tenth
coldgirl [10]

Answer: 113.1 cm^2

Step-by-step explanation: The formula to find the area of a circle is 3.14r^2. R stands for radius which is 6 in this case so just plug that in for R. 3.14(6)^2=113.1

8 0
3 years ago
Nathan needs to sell at least 75 t shirts to get a bonus he already has sold 15 red tye dye shirts and 23 solid blue ones how ma
AnnyKZ [126]

Red shirts and blue shirts equally count to his bonus, so he has 15 + 23 = 38 shirts sold at this moment. He needs to sell 75 shirts for the bonus. We subtract our goal from what he have; 75 - 38 = 37.


The strategy here: subtract the goal (75 shirts) from what you did to get to the goal (15 shirts and 23 shirts).


Nathan needs to sell 37 more shirts for the bonus. Hope this helps.

4 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST.
charle [14.2K]

Answer:

option d

Step-by-step explanation:

The cross section of the rectangular prism is parallel to the base.

So, the length and width is congruent to the base. So, same length and width

3 0
3 years ago
Find the smallest 4 digit number such that when divided by 35, 42 or 63 remainder is always 5
alex41 [277]

The smallest such number is 1055.

We want to find x such that

\begin{cases}x\equiv5\pmod{35}\\x\equiv5\pmod{42}\\x\equiv5\pmod{63}\end{cases}

The moduli are not coprime, so we expand the system as follows in preparation for using the Chinese remainder theorem.

x\equiv5\pmod{35}\implies\begin{cases}x\equiv5\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{42}\implies\begin{cases}x\equiv5\equiv1\pmod2\\x\equiv5\equiv2\pmod3\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{63}\implies\begin{cases}x\equiv5\equiv2\pmod 3\\x\equiv5\pmod7\end{cases}

Taking everything together, we end up with the system

\begin{cases}x\equiv1\pmod2\\x\equiv2\pmod3\\x\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

Now the moduli are coprime and we can apply the CRT.

We start with

x=3\cdot5\cdot7+2\cdot5\cdot7+2\cdot3\cdot7+2\cdot3\cdot5

Then taken modulo 2, 3, 5, and 7, all but the first, second, third, or last (respectively) terms will vanish.

Taken modulo 2, we end up with

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod2

which means the first term is fine and doesn't require adjustment.

Taken modulo 3, we have

x\equiv2\cdot5\cdot7\equiv70\equiv1\pmod3

We want a remainder of 2, so we just need to multiply the second term by 2.

Taken modulo 5, we have

x\equiv2\cdot3\cdot7\equiv42\equiv2\pmod5

We want a remainder of 0, so we can just multiply this term by 0.

Taken modulo 7, we have

x\equiv2\cdot3\cdot5\equiv30\equiv2\pmod7

We want a remainder of 5, so we multiply by the inverse of 2 modulo 7, then by 5. Since 2\cdot4\equiv8\equiv1\pmod7, the inverse of 2 is 4.

So, we have to adjust x to

x=3\cdot5\cdot7+2^2\cdot5\cdot7+0+2^3\cdot3\cdot5^2=845

and from the CRT we find

x\equiv845\pmod2\cdot3\cdot5\cdot7\implies x\equiv5\pmod{210}

so that the general solution x=210n+5 for all integers n.

We want a 4 digit solution, so we want

210n+5\ge1000\implies210n\ge995\implies n\ge\dfrac{995}{210}\approx4.7\implies n=5

which gives x=210\cdot5+5=1055.

5 0
3 years ago
Use a number line to add:
Jobisdone [24]
Start at 14 on the number line. Since 25 is negative you’re going to be moving to the left. After 14 hops you’ll reach zero, you’re adding -25 so you’ll have to reach a total of 25 hops to the left. You have moved so far 14 hops so you still have 11 to go. Moving 11 more hops to the left results in -11. Now you have reached the total number of hops 25, the negative sign indicated you were moving towards the left. So 14+(-25)=-11
8 0
3 years ago
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