3 years ago

-5.20 • 3.7 please help

2 answers:

8 0

It is -19.24. That’s all

6 0

Answer: -19,24

Step-by-step explanation:

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Andreyy89

$\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1$

Recall that

$\displaystyle\sum_{i=1}^n1=n$

$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$

Your sums start at $i=3$ , so in order to apply these formulas directly, you need to compensate for the missing first two terms:

$\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8$

$\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52$

$\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}$

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3 years ago

melomori [17]

Answer:bhbehrf

Step-by-step explanation:

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