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Colt1911 [192]
3 years ago
7

Please answer correctly!! I’ll mark as brainliest! No links no fake answers

Mathematics
1 answer:
ioda3 years ago
6 0
Hii I think the answer is 24!!
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Solving for angles - Geometry
Otrada [13]

Answer:

<BAC=19

Step-by-step explanation:

<AOB=<DOC=142

<BAC=<ABD

2<BAC=180-142

2<BAC=38

<BAC=38/2

<BAC=19

7 0
3 years ago
Read 2 more answers
There are 92 students that equals 75 how many students are 100 percent
elena-s [515]

Answer:

122.67 or round it to 123

Step-by-step explanation:

i used the butterfly method.

92/75 = x/100.

i multiplied 92*100=9200

then i divided it with 75.

9200/75=x

so the answer is

x=122 or 123

4 0
3 years ago
Read 2 more answers
What is the coefficient of xy2
Gre4nikov [31]

Answer:

1 is the coefficient.

There is no number Infront of variable.Hence if there is no number thrlere is 1. xysquare 1 is the coefficient,X and y are base and square is Exponent.

7 0
2 years ago
How many sides does a polygon have if the sum of its angle measures is 2700 degrees and how do you find this?
ss7ja [257]
The number of angles equal the number of sides


The number of angles calculate: (n-2)x180°

(n-2)x180°=2700°    |divide both sides by 180°

n-2=15    |add 2 to both siedes

n=13

Answer: 13 sides.


6 0
3 years ago
Read 2 more answers
We intend to estimate the average break time of Dunder Mifflin employees. From a previous study, we believe that the average tim
arsen [322]

Answer:

The minimum sample size that we should consider is of 60 employees.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

We want our 99 percent confidence interval to have a margin of error of no more than plus or minus 2 minutes. What is the smallest sample size that we should consider?

We need to find n for which M = 2, \sigma = 6

So

M = z*\frac{\sigma}{\sqrt{n}}

2 = 2.575*\frac{6}{\sqrt{n}}

2\sqrt{n} = 2.575*6

Simplifying by 2

\sqrt{n} = 2.575*3

(\sqrt{n})^{2} = (2.575*3)^{2}

n = 59.67

Rounding up

The minimum sample size that we should consider is of 60 employees.

6 0
3 years ago
Read 2 more answers
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