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Colt1911 [192]
3 years ago
7

Please answer correctly!! I’ll mark as brainliest! No links no fake answers

Mathematics
1 answer:
ioda3 years ago
6 0
Hii I think the answer is 24!!
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Could someone please assist me in getting the answer? I will give branliest.
Mrac [35]

Answer:

9

Step-by-step explanation:

You know that the the center line is equal to half the sum of the legs, because it is the midline. You add the legs together (7x+13) and (5x+7), and you get 12x+20. Divide that by 2 and you get 6x + 10. The midline is 8x-8, so you set up an equation, and get 6x+10 = 8x-8. That simplifies to 18=2x. Divide both sides by 2 and you get x = 9

5 0
4 years ago
Read 2 more answers
2x - 8 = 6<br>help please ​
sineoko [7]

Answer:

7

Step-by-step explanation:

Move the -8 to the other side and use the rule change side change sign:

2x=6+8

2x=14

Move the 2 and convert the multiplication(as its 2×x ) into division:

x= 14÷2

x=7

7 0
3 years ago
Read 2 more answers
The ratio between two no is 2:3 . if the consequent is 24 the antecendent is​
Irina18 [472]

antecedent : 16

ratio: 2 : 3

=========

antecedent : 2

consequent : 3

=============

\rightarrow \sf \dfrac{2}{3}=\dfrac{x}{24}           [ x is antecedent ]

\rightarrow \sf 2(24)=3(x)

\rightarrow \sf 48=3(x)

\rightarrow \sf x= 16

Additional information:

In the ratio, a : b  Here the "antecedent is a" and "consequent is b"

  • Learn more: brainly.com/question/23948357
8 0
2 years ago
A rectangular box is 10 in. ​wide, 10 in. ​tall, and 8 in. long. What is the diameter of the smallest circular opening through w
lutik1710 [3]

Answer:

Diameter of smallest circular opening = 12.81 in

Step-by-step explanation:

Given:-

Width of rectangular box(W)=10 in.

Length of rectangular box(L)=8 in.

Height of rectangular box(H)=10 in.

For box to fit in the smallest circular opening we need to find the diagonal of the rectangular box, therefore

diagonal of rectangular box=diameter of smallest circular opening

So,

Diagonal\ (d)=\sqrt{width^{2}+length^{2}  }

d=\sqrt{W^{2} +L^{2} }

d=\sqrt{10^{2}+8^{2}}

d=\sqrt{100+64}

d=\sqrt{164}

d=12.81\ in.

\therefore\ diagonal\ (d)=12.81\ in

Therefore diameter of smallest circular opening = 12.81 in.

8 0
4 years ago
X+3 over X+2= X+5 over X
TiliK225 [7]
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4 0
4 years ago
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