Anyone good at trigonometry please help

Suppose that the commuting time on a particular train is uniformly distributed between 42 and 52 minutes. Bold a. What is the pr

nikdorinn [45]

Answer: 0.2

Step-by-step explanation:

Given: The commuting time on a particular train is uniformly distributed over the interval (42,52).

∴ The probability density function of X will be :-

$f(x)=\dfrac{1}{b-a}\\\\=\dfrac{1}{52-42}=\dfrac{1}{10}, 42$

Thus, the required probability :-

$P(X$

Hence, the probability that the commuting time will be less than 44 minutes= 0.2

7 0

2 years ago

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0

2 years ago

P(Girl Sophomore) :<br> =[?]

marusya05 [52]

Probability helps us to know the chances of an event occurring. The probability being a Sophomore given she is a girl is 1/3.

<h3>What is Probability?</h3>

Probability helps us to know the chances of an event occurring.

$\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}$

The probability of being a girl and Sophomore is 9/37. While the probability of being a girl is 27/37. Therefore, the probability being a Sophomore given she is a girl is,

P(Girl l Sophomores) = P(Girl and Sophomore)/ P(Girl)

= (9/37) / (27/37)

= 9 / 27

= 1/3

Hence, the probability being a Sophomore given she is a girl is 1/3.

Learn more about Probability:

brainly.com/question/795909

#SPJ1

3 0

1 year ago

Read 2 more answers

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