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4 years ago

Please help me round 34,699 to the nearest ten thousand

1 answer:

4 0

Okay so rounding to the ten thousand will mean you are looking at the 3 and looking behind it, the 4 is behind the 3 in 34,699 and 0-4 we round down so the nearest 10,000 is 30,000. ANSWER: 30,000

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What is the slope of the line that passes through the points (6,-5) and (6,-8

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The slope would be undefined.

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3 years ago

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A discounted concert ticket costs $14.50 less than the original price p. You pay $53 for a discounted ticket. Write an equation

Romashka [77]

Answer:

answer ; https://socratic.org/questions/a-discounted-concert-ticket-costs-14-50-less-than-the-original-price-p-you-pay-5#585652

Step-by-step explanation:

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3 years ago

Factor the expression 3x^2 - 15x<br> i will mark brainliest

tensa zangetsu [6.8K]

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3 years ago

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Find the solutions to the following linear-quadratic systems algebraically. Select the ordered pair that is one of the correct s

Ghella [55]

Answer:

(-2, 6)

Step-by-step explanation:

we have

$y=x^{2} +3x+8$ ----> equation A

$y=2x+10$ ----> equation B

equate equation A and equation B

$x^{2} +3x+8=2x+10$

$x^{2} +3x+8-2x-10=0$

$x^{2} +x-2=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +x-2=0$

$a=1\\b=1\\c=-2$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-2)}} {2(1)}$

$x=\frac{-1\pm\sqrt{9}} {2}$

$x=\frac{-1\pm3} {2}$

$x=\frac{-1+3} {2}=1$

$x=\frac{-1-3} {2}=-2$

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For x=-2

$y=2(-2)+10=6$

therefore

The solutions are (1,12) and (-2,6)

3 0

3 years ago

Solve for all possible values of x. square root of the quantity x minus 8 end quantity minus 3 equals 1

Digiron [165]

Answer:

x = 24

Step-by-step explanation:

In a radical equation it is critical to start by isolating the root that contains the unknown on one side of the equal sign, so we do such by adding 3 to both sides:

$\sqrt{x-8} -3 = 1\\\sqrt{x-8} -3+3 = 1+3\\\sqrt{x-8} = 4$

Next we square both sides of the equation to free the unlnown from the square root:

$(\sqrt{x-8})^2 = (4)^2\\x-8=16\\x=16+8\\x=24$

We found x by adding 8 on both sides. Therefore x=24.

One can check the answer by replacing x by 24 in the original equation.

5 0

3 years ago

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