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vovangra [49]
3 years ago
13

Please help me round 34,699 to the nearest ten thousand

Mathematics
1 answer:
Serhud [2]3 years ago
4 0
Okay so rounding to the ten thousand will mean you are looking at the 3 and looking behind it, the 4 is behind the 3 in 34,699 and 0-4 we round down so the nearest 10,000 is 30,000. ANSWER: 30,000
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Viefleur [7K]
The answer is 105 kilometers
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4 0
3 years ago
Find the area of the quadrilateral ABCD. ​
REY [17]
Answer
—————————————-

3 0
2 years ago
Can someone help me with this question
Mashcka [7]
The correct answer here would be D. -1(3x+1)(x+5). You can find this answer by redistributing the problem.

-1(3x+1)(x+5)
-1(3x²+15x+1x+5)
-1(3x²+16x+5)
-3x²-16x-5

Using the math above, we can see that when we redistribute we get the original equation. That makes Choice D correct.
5 0
3 years ago
How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
3 years ago
Evaluate |-3|<br><br> ±3<br> -3<br> 3
marin [14]

Answer:

Its just 3

Step-by-step explanation:

Because its absolute value.

Hope this helps!

4 0
3 years ago
Read 2 more answers
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