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Varvara68 [4.7K]
3 years ago
15

What is the area of the trapazoid

Mathematics
2 answers:
Greeley [361]3 years ago
6 0

Answer:

Step-by-step explanation:

The formula is a + b/2 *h

murzikaleks [220]3 years ago
5 0
A+b/2 •h that’s the formula
You might be interested in
Please help I’ll give brainliest
bekas [8.4K]

Answer:

Total area:75

Step-by-step explanation:

Rectangle area=6×5=30

triangle area=(18×5)/2=45

total area: 30+45=75

5 0
3 years ago
Read 2 more answers
Marie spends $450.00 at a department store. She has two coupons: one for a 15% discount and one for $50 off any purchase above $
VMariaS [17]

Answer:

Her first coupon ti be used is $50 off a purchase above $300

Final purchase price= $340

Step-by-step explanation:

Marie has two coupons

one for a 15% discount and one for $50 off any purchase above $300.

The stores allow the two coupons to be combined and she spends a total of $450.

Her first coupon ti be used is $50 off a purchase above $300.

So Marie have $400 now

15% off $400= 400-(0.15*400)

15% off $400 = 400-60

15% off $400 =$ 340

6 0
3 years ago
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Find the value of x when 2(x - 3) + 1 = 3x + 4<br> A) -1 <br> B) -1/5<br> C) -9/5<br> D) -9
Virty [35]
-1/5 is the answer because I have had this question before and I got it right


6 0
3 years ago
Read 2 more answers
Find the value of x in the following quadrilateral
vlabodo [156]

Answer:

The answer is 63.31

Step-by-step explanation:

2x - 5 + 3x - 42 + x +  \frac{3}{7} x = 360 \\  \frac{45}{7} x = 360 + 47 \\ x = 63.31

6 0
3 years ago
PLEASE HELP
lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function j\left(x\right) \ = \ 4^{x-2}, hence the average rate of change (slope of the blue line) between the x and x+h is

                     \text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\  \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}

                                                            \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}

7 0
2 years ago
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