I'm assuming that since 87% failed, that would the remaining 13% was a success. If that assumption is correct, than we simply have to take:
.13 * 13531 = 1759.03 products were successful.
Answer:
Bottom left corner and bottom right corner
Step-by-step explanation:
probability of drawing ace: 4/52 = 1/13
probability of drawing 9: 4/52 = 1/13
probability of drawing ace or 9: 1/13 + 1/13 = 2/13 or ~15.4%
8/10 is the answer to this problem
For a two-tailed test we need to halve 0.01, giving 0.005. Then we need to sutract 0.005 from 0.5, giving 0.5 - 0.005 = 0.495. Looking up the p value of 0.495 in an inverse normal probability table we obtain the value z = 2.5758. Therefore the critical values are -2.5758 and 2.5758.
