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Stolb23 [73]
3 years ago
6

Please help!!!! I obviously don’t need 10,11,and 12

Mathematics
1 answer:
tatyana61 [14]3 years ago
3 0
For 1-5, you add up both angles that are stated and then subtract that number from 180 to get the missing angle.
For 6, the top angle is equal to 40 since half of it equals 20. The other 2 angles are equivalent, so we subtract 40 from 180 and then divide that number by 2 to get your answer.
For 7, you see two triangles on one. The first triangle has the angles of 60 and 60, and since a triangles angles add up to 180, we add both angles and subtract it from 180 to get that side. Since a straight angle is also equal to 180 degrees, the answer you just got and the answer you’re looking for are supplementary angles. So, you subtract that answer from 180 to get your answer.
For 8, you do the same thing with supplementary angles. Since the straight lines is equal to 180 degrees, we subtract 144 from it to get your answer.
For 9, we do the same thing that we did with number 7. The first triangles sides are 40 and 70, so we add those together and subtract it from 180 to get the missing side. That side and the one that you’re looking for are supplementary angles, so you subtract that side from 180 to get your answer.
You might be interested in
Find a closed-form solution to the integral equation y(x) = 3 + Z x e dt ty(t) , x > 0. In other words, express y(x) as a fun
MrMuchimi

Answer:

y{x} = \sqrt{7+2Inx}

Step-by-step explanation:

y(x)= 3 + \int\limits^x_e {dx}/ \, ty(t) , x>0}

Let say; By y(x)= y(e)  

we have;  

y(e)= 3 + \int\limits^e_e {dt}/ \, ty= 3+0

Using Fundamental Theorem of Calculus and differentiating by Lebiniz Rule:

y^{1} (x) = 0 + 1/ xy

y^{1} = 1/xy  

dy/dx = 1/xy  

\int\limits {y} \, dxy = \int\limits \, dx/x

y^{2}/2 Inx + C

RECALL: y(e) = 3  

(3)^{2} / 2 = In (e) + C  

\frac{9}{2} =In(e)+C  

\frac{9}{2} - 1 = C

\frac{7}{2} = C  

y^{2} / 2 = In x +C

y^{2} / 2 = In x +7/2

MULTIPLYING BOTH SIDE BY 2 , TO ELIMINATE THE DENOMINATOR, WE HAVE;

y^{2} = {7+2Inx}  

y{x} = \sqrt{7+2Inx}

8 0
3 years ago
Please help me with this.
tatyana61 [14]

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

  1. r (- 3) = 15
  2. r (- 1) = 11
  3. r (1) = - 7
  4. r (5) = 13

<h3>How to evaluate a piecewise function at given values</h3>

In this question we have a <em>piecewise</em> function formed by three expressions associated with three respective intervals. We need to evaluate the expression at a value of the <em>respective</em> interval:

<h3>r(- 3): </h3>

-3 ∈ (- ∞, -1]

r(- 3) = - 2 · (- 3) + 9

r (- 3) = 15

<h3>r(- 1):</h3>

-1 ∈ (- ∞, -1]

r(- 1) = - 2 · (- 1) + 9

r (- 1) = 11

<h3>r(1):</h3>

1 ∈ (-1, 5)

r(1) = 2 · 1² - 4 · 1 - 5

r (1) = - 7

<h3>r(5):</h3>

5 ∈ [5, + ∞)

r(5) = 4 · 5 - 7

r (5) = 13

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

  1. r (- 3) = 15
  2. r (- 1) = 11
  3. r (1) = - 7
  4. r (5) = 13

To learn more on piecewise functions: brainly.com/question/12561612

#SPJ1

7 0
2 years ago
a number is equal to twice a smaller number plus 3. The same number is equal to twice the sum of the smaller number and1. How ma
NeX [460]

Answer:

There is NO solution

Step-by-step explanation:

Considering 'y' be the number

Considering x be the smaller number

As 'y' is equal to twice a smaller number plus 3.

so

y = 2x + 3

also

y is equal to twice the sum of the smaller number and 1.

so

y = 2x + 1

so the system of equations become

y = 2x + 3

y = 2x + 1

solving

\begin{bmatrix}y=2x+3\\ y=2x+1\end{bmatrix}

\mathrm{Subsititute\:}y=2x+1

\begin{bmatrix}2x+1=2x+3\end{bmatrix}

\mathrm{Refine\:}2x+1=2x+3

-2=0

-2=0\:\mathrm{\:is\:false,\:therefore\:the\:system\:of\:equations\:has\:no\:solution}

\mathrm{No\:Solution}

Therefore, there is NO solution.

7 0
3 years ago
The rule T 5, -0.5° Ro, 1800(x, ) is applied to FGH to
Yuki888 [10]

Answer:

Step-by-step explanation:

Given rule for the multiple translations is,

T_{5,-0.5}.R_{0.180^{\circ}}(x,y)

Apply the rule R_{0,180^{\circ}} first.

(x, y) → (-x, -y)

This rule illustrates a rotation of the triangle FGH by 180° about the origin,

Vertices of ΔFGH are,

F → (1, 1)

G → (4, 5)

H → (5, 1)

After rotation vertices of the image triangle are,

F' → (-1, -1)

G' → (-4, -5)

H' → (-5, -1)

Further apply the rule,

T_{5,-0.5}

(x, y) → (x + 5, y - 0.5)

By this rule of translation,

F'(-1, -1) → F"{(-1 + 5), (-1 - 0.5)}

            → F"(4, -1.5)

G'(-4, -5) → G"[(-4 + 5), (-5 - 0.5)]

              → G"(1, -5.5)

H'(-5, -1) → H"[(-5 + 5), (-1 -0.5)]

             → H"(0, -1.5)

8 0
2 years ago
Use the grouping method to factor this polynomial completely.<br> 3x3 + 12x2 + 2x + 8
dezoksy [38]

Answer:

(3x^2 + 2)(x + 4).

Step-by-step explanation:

3x3 + 12x2 + 2x + 8

3x^2(x + 4) + 2(x + 4)   The  x + 4 is common to the 2 groups so we have:

(3x^2 + 2)(x + 4).

3 0
3 years ago
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