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2 years ago

8

How are units of measurement chosen and interpreted in formulas?

1 answer:

mamaluj [8]2 years ago

3 0

Unit of measurement in a formula suggests a definite magnitude of a certain quantity. For instance, there are basic unit of measurement for the 7 basic quantities: These are
1. seconds (s) for time
2. meter (m) for length
3. candela (cd) for luminous intensity
4. Ampere (A) for electric current
5. Kelvin (K) for Temperature
6. Kilogram (kg) for mass
7. mole (mol) for amount of substance
These units of measure should be homogenous in a formula for easy interpretation. Other derived quantities (e.g volume) also have their corresponding units as well as those quantities which are not based on the metric systems (e.g Celsius, pounds, etc)

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A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5

lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 0.499, \sigma = 0.002$

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{0.504 - 0.494}{0.002}$

$Z = 2.5$

$Z = 2.5$ has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{0.496 - 0.494}{0.002}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0

3 years ago

If you are reading this please help!!!!

Soloha48 [4]

Given:

$1. -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$$

To find:

The product of the polynomials.

Solution:

1. $-3 x^{2}\left(4 x^{3}-7\right)$ $=-3 x^{2}(4 x^{3}) -3 x^{2}(-7)$

Multiply the numerical coefficient and add the powers of x.

$=-12 x^{5}+21 x^{2}$

2. $(6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)$

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

$=12 x^2+18x-10 x-15$

$=12 x^2+8x-15$

3. $(3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)$

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

$=3x^{3}+15 x^2-6x-x^{2}-5 x+2$

Add or subtract like terms together.

$=3x^{3}+14 x^2-11x+2$

The answer for multiplying polynomials:

$1. -12 x^{5}+21 x^{2}$

$2. \ 12 x^2+8x-15$

$3. \ 3x^{3}+14 x^2-11x+2$

3 0

3 years ago

Solve the system of equations below.

trapecia [35]

Answer:

A) x + y = 8

B) 3x + 2y = 21

We multiply A) by -2

A) -2x -2y = -16 Then we add this to

B) 3x + 2y = 21

x = 5

y = 3

Second answer is correct

Step-by-step explanation:

5 0

3 years ago

Identify the augmented matrix that represents this liner system <br> 2x-3y=4 <br> 5x+7y=39

Lisa [10]

Answer:

its c edg 2020

Step-by-step explanation:

7 0

2 years ago

-24 divided by the fraction 4 over 8

julsineya [31]

Answer:

-48

Step-by-step explanation:

6 0

2 years ago