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3 years ago

Help me on this one asap tyyy

Mathematics

1 answer:

Kryger [21]3 years ago

4 0

Answer:

The answer is R

Explanation:

Since there are 4 sides, we divide 360 by 4 to find the amount needed to turn to move from one side to another. So we move P one side, landing on Q, then we move it 3 sides counter-clockwise (270/90=3 sides), landing on R

Hope it helps!

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5c=d for c I need help with answering this math problem

Andrei [34K]

Step-by-step explanation:

Let's solve for c.

5c=d

Step 1: Divide both sides by 5.

3 0

2 years ago

64/143 - 21/208 what does it equal to and how?

Arlecino [84]

2 11/78 you just have to simply multiply 64/143 x2 because since it can't be subtracted. And after you multiply 64/143, you just have to subtract normally which is 128-21 and 286-208. Then since your answer came out to an improper fraction, so you have to simplify by dividing 107 divided by 78. Then you will get your answer which is 2 11/78.

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2 years ago

I am in 9th grade,if you have 889,865x999,786 what doe it equal also yes i am not in virtual school and teacher will not let me

RSB [31]

Answer:

889674568890

Step-by-step explanation:

I used a calculator :)

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2 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection.

This means that,

Probability that at least one of them needs replacement at the first inspection =

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

The point G(6,4) is rotated 180° clockwise around the origin. What

siniylev [52]

Answer:

Step-by-step explanation:

when (x,y) is rotated through 180 then new coordinates are (-x',-y')

G(6,4)→G'(-6,-4)

5 0

2 years ago