The answer would be disagree because it you reflected it over the x axis then it would be in the third quadrant
Hope this helps
Have a great day/night
Feel free to ask any questions
They will have planted the same amount of trees on the 4th day.
Find the first semicircle area
Area semicircle can be determined by dividing the full area of circle by 2.
The first semicircle radius is 5 cm
semicircle area = 1/2 circle area
semicircle area = 1/2 × π × r²
semicircle area = 1/2 × 3.14 × 5²
semicircle area = 1/2 × 3.14 × 25
semicircle area = 39.25 cm²
Find the second semicircle area
Because the dimension of the second semicircle is congruent to the first semicircle, they have similar area measurement, 39.25 cm².
Find the quarter circle area
The area of quarter circle can be determined by dividing the full area of a circle by 4.
q circle = 1/4 × area of circle
q circle = 1/4 × π × r²
q circle = 1/4 × 3.14 × 10²
q circle = 1/4 × 314
q circle = 78.5 cm²
To find the entire area, add the area above together
area = first semicircle + second semicircle + q circle
area = 39.25 + 39.25 + 78.5
area = 157
The area of shaded region is 157 cm²
It’s d
You just have to keep on substitutes x or y . I added a picture hope that helps
Answer:
1.
The slope is 2
The y-intercept is -10
equation: y = 2x - 10
2.
Slope: 2.5
y-intercept: 1
Equation: y = 2.4x + 1
Step-by-step explanation:
1.
x y
2 12
4 16
8 24
10 28
from 12 to 16 you add 4
from 2 to 4 you add 2
y/x = 4/2 = 2
The slope is 2
The y-intercept is -10
equation: y = 2x - 10
I got the y-intercept because I went from 12 to 0 which is -12, and then 2 - 12 and it's -10
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2.
x y
5 4
20 10
30 14
35 16
from 4 to 10, u add 6
from 5 to 20 you add 15
y/x = 15/6 = 2.5
Slope: 2.5
y-intercept: 1
Equation: y = 2.4x + 1
I got the y-intercept because I went from 4 to 0 which is -4, and 5 - 4 is 1.
Hope this helped
