The compound inequality that represents the two following scenarios are:
- 65 < f ≤ 4
- 8 ≤ f ≤ 12
A compound inequality usually puts together two or more simple inequalities statements together.
Following the assumption from the given information that;
- a free single scoop cone = f
<h3>1.</h3>
The age group of individuals designated to receive the free single scoop cones is:
- people who are older than 65 i.e. > 65
- children that are 4 or under 4 i.e. ≤ 4
Thus, the compound inequality that is appropriate to express both conditions is:
<h3>
2.</h3>
- On Tuesdays, the least amount of flavors = 8
- The addition amount of extra flavors they can add = 4
Now, we can infer that the total amount of flavors = 8 + 4 = 12
Thus, the compound inequality that is appropriate to express both conditions is:
- Least amount of flavors ≤ f ≤ total amount of flavors
- 8 ≤ f ≤ 12
Therefore, we can conclude that the compound inequality that represents the two following scenarios are:
- 65 < f ≤ 4
- 8 ≤ f ≤ 12
Learn more about compound inequality here:
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The average rate of change from x = -1 to x = 2 is 2
<u>Solution:</u>
Given function is:
f(x) = 2x - 1
We have to find the average rate of change from x = -1 to x = 2
<em><u>The average rate of change is given as:</u></em>

<em><u>The average rate of change from x = -1 to x = 2 is given by formula:</u></em>

<em><u>Find f(2) and f( - 1)</u></em>
<em><u>Substitute x = 2 in given function</u></em>
f(2) = 2(2) - 1 = 4 - 1 = 3
<em><u>Substitute x = -1 in given function</u></em>
f( - 1) = 2(-1) - 1 = -2 - 1 = -3
<em><u>Substitute the values in above formula,</u></em>

Thus average rate of change from x = -1 to x = 2 is 2
The order does not matter, so we will be using combinations here. 52C1 is the first one since there is only one possibility. 16C1 is the second. You have to multiply these two, so 52 X 16 = 832.
15 i am pretty sure i’m probably gonna be wrong
Answer:
I think it's y-y[1] = m(x-x[1])
Step-by-step explanation:
the ones in the parentheses are like smaller near the bottom of the y and/or x btw.
Good luck! :)