(1, 3.5 ) and (3, 3.5 )
the endpoints of the midsegment are at the midpoints of DE and DF
using the midpoint formula with D(0, 7), E(2, 0), F(6, 0)
midpoint of DE = [(0 + 2),(7 + 0)] = (1, 3.5)
midpoint of DF = [(0 + 6),(7 + 0)] = (3, 3.5)
Answer:
yes
Step-by-step explanation:
that it has a radius of (84/(h×pi))^1/3