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spin [16.1K]
3 years ago
10

Examples of pure and impure substances

Chemistry
2 answers:
erastova [34]3 years ago
8 0
Pure- table salt
Impure- vegetable oil
Sladkaya [172]3 years ago
8 0

Examples of pure substances are water, diamond, table salt

Examples of impure substances are muddy water, air, sugar in water

<u>Explanation</u>:

  • A pure substance is one that is made up of only one element or one chemical compound. It has no impurities. They can be elements or compounds.
  • It has definite properties and composition.
  • Examples are water, diamond, table salt, etc.
  • An impure substance is one that is made up of two or more elements or compounds that are not chemically bonded. It is a mixture.
  • It has no definite composition or properties.
  • Examples are muddy water, sugar in water, air, etc.
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What happens when phenol is treated with bromine water?
aleksley [76]

Answer:

Polyhalogen derivatives are given when Phenol is treated with bromine water, in which all the H-atoms present at the o- and p- positions are substituted by Bromine with respect to the -OH group.

hope it helps

thanku

Explanation:

4 0
2 years ago
At room temperature (208C) and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less tha
Ugo [173]

Total density of filled ball with nitrogen gas: \frac{0.12G+0.6524g}{0.560L} = 1.3792g/L

The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). The ball filled with nitrogen will not float in the air because total density of filled ball is greater than the density of an air. Density of the evacuated ball D = 0.214 g/L

Density of nitrogen gas = d_4=1.165g/L

Mass of the nitrogen gas : 1.165g/L \times 0.560L = 0.6524g

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4 0
1 year ago
A student dissolves 15.0 g of ammonium chloride(NH4Cl) in 250. 0 g of water in a well-insulated open cup. She then observes the
iren2701 [21]

Answer:  

1) Endothermic.  

2) Q_{rxn}=4435.04J  

3) \Delta _rH=15.8kJ/mol

Explanation:  

Hello there!  

1) In this case, for these calorimetry problems, we can realize that since the temperature decreases the reaction is endothermic because it is absorbing heat from the solution, that is why the temperature goes from 22.00 °C to 16.0°C.  

2) Now, for the total heat released by the reaction, we first need to assume that all of it is released by the solution since it is possible to assume that the calorimeter is perfectly isolated. In such a way, it is also valid to assume that the specific heat of the solution is 4.184 J/(g°C) as it is mostly water, therefore, the heat released by the reaction is:

Q_{rxn}=-(15.0g+250.0g)*4.184\frac{J}{g\°C}(16.0-20.0)\°C\\\\ Q_{rxn}=4435.04J    

3) Finally, since the enthalpy of reaction is calculated by dividing the heat released by the reaction over the moles of the solute, in this case NH4Cl, we proceed as follows:

\Delta _rH=\frac{ Q_{rxn}}{n}\\\\\Delta _rH= \frac{ 4435.04J}{15.0g*\frac{1mol}{53.49g} } *\frac{1kJ}{1000J} \\\\\Delta _rH=15.8kJ/mol

Best regards!  

Best regards!

4 0
3 years ago
Classify each element as a metal, nonmetal, or semimetal. br in cr ca drag the appropriate items to their respective bins. view
goldenfox [79]
Below is the distribution of given elements and additional elements in their respective bins.

Iron, Magnesium, Aluminium, Calcium, Chromium and Indium are classified as Metals due to their hardness, conduction of current and heat, Solid state, formation of metallic bonding and prefers to form cations e.t.c

Oxygen, Neon and Bromine are classified as non-metals. Non-metals are mostly gases except for Bromine. They are highly volatile and prefers to form anions.

Semimetals are those metals which have both properties of metals and non-metals and are also called as metalloids.

6 0
3 years ago
You are running a lemonade stand with your friend. You prepared 10 liters of 0.7 molarity lemonade, but your friend did online r
olga nikolaevna [1]

Answer:

add 7.5L of water

Explanation:

M1×V1=M2×V2

M is molarity, V is volume

0.7 × 10 = 0.4 × V2

V2= 17.5L

vol. of water to add= 17.5 - 10 = 7.5L

3 0
3 years ago
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