Answer:
4.806 g ≤ n ≤ 5.194 where n is the mass of a nickle.
Step-by-step explanation:
The problem tells us the weight can vary by .194 g, this means it can be up to .194 lighter and 194 heavier. Well what value is .194 lighter and .194 heavier? 4.806 and 5.194 respectively. So that means a nickle can be anywhere in that range, which tells us the inequality.
Answer:
39 and 86.
Step-by-step explanation:
39 and 86 equal 125 when added. When 47 is subtracted from 86 you get 39.
We can not really tell in this question as you dont know the equation that is being used for the domain and range relationship but overall one should know that:
The set of values of the independent variable(s) for which a function or relation is defined as the domain of a function. Typically, this is the set of x-values that give rise to real y-values.
The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain.
2 times the square root of 5 . that’s what i got .
14 over 4509 would be an equvilent fraction
