All categories

4 years ago

Use the functions f(x) = 4x − 5 and g(x) = 3x + 9 to complete the function operations listed below.

1 answer:

5 0

Hello :
f(x) = 4x − 5 and g(x) = 3x + 9
(f + g)(x) = f(x) +g(x) = (4x-5) +(3x+9)
(f + g)(x) =7x +4
(f ⋅ g)(x) = f(x) × g(x) = (4x-5)(3x+9) = 12x² +36x -15x-45
(f ⋅ g)(x) = 12x² +21x -45
f[g(x)] = f(3x+9) = 4(3x+9) -5
f[g(x)] = 12x +31

You might be interested in

What Is The Prime Factor Of 4275 ?

jarptica [38.1K]

Answer:

$5^2$ · $3^2$ · $19$

Step-by-step explanation:

Well to find the prime factor we make the prime factorization tree.

Look at the image below↓

Thus,

the prime factorization of 4275 is $5^2$ · $3^2$ · $19$

Hope this helps :)

4 0

3 years ago

I need some help with this one I'm lost!

SpyIntel [72]

Answer:

-334

Step-by-step explanation:

tyes sfdfa d

3 0

3 years ago

I need answers for #3 and #4

NNADVOKAT [17]

Answer:#3- C. E=155

#4- I think it's G‍♀️

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cfrak%7B%20%5Corange%7B%20Question%7D%7D" id="TexFormula1" title=" \large\frak{ \

SVEN [57.7K]

Answer:

$\boxed{\sf distance \: between \: the \: objects \: \: is \: 2.5 \: cm}$

Step-by-step explanation:

According to universal law of gravitation every object in the universe attracts every other particles that surrounds it with a force which is inversely proportional to the square of their distance of separation & directly proportional to

the product of their masses, given by standard formula.

$A = G \cdot \frac{m_1.m_2}{ {d}^{2} }$

where A,d & G are force of attraction, distance of separation & proportionality constant respectively.

Given:

A1 = 2 units

d1= 5 cm

A2 = 8 units

To find:

Distance of separation when the force of attraction is 8 units d2 = ?

Solution:

Substituting the given values in above at each point,

$A_1 = G \cdot \frac{m_1.m_2}{ {d_1}^{2} } \\ 2 = G \cdot \frac{m_1.m_2}{ {5}^{2} } \\ \sf similarly \: at \: second \: point \: of \: attraction \\ A_2 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ 8 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ \sf \: \: dividing \: both \: of \: the \: equation \\ \frac{2}{8} = \frac{G \cdot \frac{m_1.m_2}{ {5}^{2} }}{G \cdot \frac{m_1.m_2}{ {d_2}^{2} } } \\ \sf \: G \: m_1 and \: m_2 \: are \: \: constant \: hence \\ \sf they \: can \: be \: cancelled \: out \\ \frac{2}{8} = \frac{ \frac{1}{ {5}^{2} } }{ \frac{1}{ {d_2}^{2} } } \\ \sf rearranging \: above \: equation \\ \frac{1}{4} = \frac{{d_2}^{2} }{ {5}^{2} } \\ {d_2}^{2} = \frac{ {5}^{2} }{4 } \\ {d_2}^{2} = \frac{25}{4} \\ {d_2}^{2} = 6.25 \\ \sqrt{{d_2}^{2} } = \sqrt{6.25} \\ \boxed{ \sf{d_2} = 2.5 \: cm}$

Answer: the distance between the two objects is 2.5 cm, if the attraction between them is 8 units.

Learn more about universal law of gravitation here brainly.com/question/27244479

Thanks for joining brainly community!

7 0

2 years ago

What is the answer ?

Rzqust [24]

Hope This Helped and GOOD LUCK!!!!!!! :D

3 0

3 years ago