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serious [3.7K]
2 years ago
11

A map has a scale of 1 in. : 38 ft use the given map distance to find the actual distance

Mathematics
1 answer:
Dvinal [7]2 years ago
8 0

Answer:

for q 19 its x=209ft and for 21 its 66.5 ft i forgot q 20

Step-by-step explanation:

You might be interested in
The expression 7z-9p+9z-z
nika2105 [10]

Answer:

15z - 9p

Step-by-step explanation:

7z - 9p + 9z - z

=7z - 9p +8z

= -9p + 15z or 15z - 9p Answer

Hope this helps!

4 0
3 years ago
A sign standing 6 feet tall is situated 18 feet away from a flag pole. at a certain time of day the sign's shadow is 3 feet long
alexdok [17]
Observe attached picture.

On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft

When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.

We can apply trigonometry rules to find height of flagpole.

From small triangle containing sign we can find tangens function:
tan \alpha = \frac{C}{D}
Similarly we can do for large triangle containing flagpole:
tan \alpha = \frac{A}{B}

We see that these two equations have same left sides. This means that their right sides must also be same:
\frac{C}{D} = \frac{A}{B}
We can solve for A:
CB=AD \\ A= \frac{CB}{D}  \\ A= \frac{6*24}{3}  \\ A=48 ft

Height of flagpole is 48 feet.

8 0
3 years ago
I need help with number 1 please
Bond [772]
306 / 3.6 = 85 gallons per minute

5,200 = 85x
x = <span>61.1764705882

hope this helps</span>
4 0
2 years ago
Read 2 more answers
Use the value of the first integral I to evaluate the two given integrals. I = integral^3_0 (x^3 - 4x)dx = 9/4 A. integral^3_0 (
Troyanec [42]

Answer:

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that I=\int_0^3 x^3-4x dx=9/4. We use the properties of integrals to write the new integrals in terms of I.

A) \int_0^3 8x-2x^3 dx=\int_0^3 -2(x^3-4x) dx=-2\int_0^3 x^3-4x dx=-2I=-9/2. We have used that ∫cf dx=c∫f dx.

B) \int_3^0 4x - x^3 dx=-\int_0^3 (4x-x^3) dx=\int_0^3-(4x-x^3) dx=\int_0^3 x^3-4x dx=I=9/4. Here we used that reversing the limits of integration changes the sign of the integral.

C) It's the same integral in A)

4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
coldgirl [10]

Answer:

z = -0.4.

Step-by-step explanation:

Here's the formula for finding the z-score (a.k.a. standardized normal variable) of one measurement x of a normal random variable X \sim N(\mu,\; \sigma^{2}):

\displaystyle z = \frac{x-\mu}{\sigma},

where

  • z is the z-score of this measurement,
  • x is the value of this measurement,
  • \mu is the mean of the random normal variable, and
  • \sigma is the standard deviation (the square root of variance) of the random normal variable.

Let the length of a trout in this lake be X inches.

X \sim N(30, \; 4.5^{2}).

  • \mu = 30, and
  • \sigma = 4.5.

For this measurement, x = 28.2. Apply the formula to get the z-score:

\displaystyle z = \frac{x - \mu}{\sigma} = \frac{28.2 - 30}{4.5} = -0.4.

5 0
3 years ago
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