Answer:
sorry i dont know
Step-by-step explanation:
Answer:
y=-3/16(x-8)^2+12
Step-by-step explanation:
Refer to the vertex form equation for a parabola:
y=a(x-h)^2+k where (h,k) is the vertex.
Therefore, we have y=a(x-8)^2+12 as our equation so far. If we plug in (16,0) we can find a:
0=a(16-8)^2+12
0=64a+12
-12=64a
-12/64=a
-3/16=a
Therefore, your final equation is y=-3/16(x-8)^2+12
The picture in the attached figure
step 1we know that
It is given that AD and BD are bisectors of ∠CAB and ∠CBA respectively.
Therefore,
x = ∠CAB/2 -----> equation 1
y = ∠CBA/2 -----> equation 2
step 2In triangle ABC,
∠CAB + ∠CBA + ∠ACB = 180° ----> [The sum of all three angles of a
triangle is 180°]
∠CAB + ∠CBA + 110° = 180°
∠CAB + ∠CBA = 180° - 110°
∠CAB + ∠CBA = 70° ------> divide by 2 both sides
∠CAB/2 + ∠CBA/2 = 70/2 -------> equation 3
substitute equation 1 and equation 2 in equation 3
x+y=35
hence
the answer isx+y =35°
⇒ x + y = 35° ...[From equation (1) and (2)]
Answer:
We know, if we multiply a number x by its multiplicative inverse, the result is 1. So, 0.3 is the multiplicative inverse of 313.
The right choice is: A <em>whole</em> number constant could have been <em>subtracted</em> from the <em>exponential</em> expression.
Let be an <em>exponential</em> function of the form
, where
and
are <em>real</em> numbers. A <em>horizontal</em> asymptote exists when
, which occurs for
.
For this function, the <em>horizontal</em> asymptote is represented by
and to change the value of the asymptote we must add the <em>parent</em> function by another <em>real</em> number (
), that is to say:
(1)
In this case, we must use
to obtain an horizontal asymptote of -3. Thus, the right choice is: A <em>whole</em> number constant could have been <em>subtracted</em> from the <em>exponential</em> expression.
To learn more on asymptotes, we kindly invite to check this verified question: brainly.com/question/8493280